Answer:
Hg
Explanation:
We are given information about the unknown element, and using each characteristic, we can narrow down the possible elements until we have just one possibility left.
Conducts electricity: This means that the element has to be a metal, or a semi-metal, because non-metals cannot conduct electricity.
Forming chloride and oxide ions: When it is seen that it forms chloride and oxide ions in the form of XCl₂ and XO, it can be seen that this element has an ionic charge of +2. This narrows it down to the elements in <u>Group 2.</u>
Liquid at room temperature: This is tricky, because we realize that there are no elements in group 2 that are liquid at room temperature. So hence we can look at groups 3 to 12, and see if there are any liquid metals with an ionic charge of +2.
Taking all this information into account, we can see that the only element it can be is mercury (Hg).
Answer:
what is the question i don't understand
<span>ionic compounds usually involve a metal and a non metal, and non ionic (or covalent) bonds are usually between 2 non metals
a) Fe3P2 Iron is a metal, Phosphorus is a non metal so it is likely to be non ionic
p.s metals are on the left of the periodic table and non metals on the right</span>
Answer:
CaCO3 + 2HCl = CaCl2 + CO2 + H2O
Explanation:
CaCO3 + HCl = CaCl2 + CO2 + H2O
Error in equation should be HCl on left hand side not HC
Left Side
Ca = 1
C = 1
O = 3
H = 1
Cl = 1
Right Side
Ca = 1
C = 1
O = 3
H = 2
Cl = 2
So we'll try and balance the Chlorine
CaCO3 + 2HCl = CaCl2 + CO2 + H2O
Left Side
Ca = 1
C = 1
O = 3
H = 2
Cl = 2
Right Side
Ca = 1
C = 1
O = 3
H = 2
Cl = 2
Yay it worked
Answer:
3.42×10²¹ of particles
Explanation:
To determine the number of particles we should know, that:
1 mol of anything contains 6.02×10²³ particles
Therefore we have to find out, how many moles corresponds to 0.332 g of NaCl.
The conversion is: 0.332 g / 58.44 g/mol = 0.00568 moles
The rule of three to determine the number of particles is:
1 mol of NaCl has 6.02×10²³ particles
0.00568 moles must have (0.00568 . 6.02×10²³ particles )/1 = 3.42×10²¹
