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Neko [114]
4 years ago
7

WHOEVER GET IT RIGHT GETS 50 POINTS

Physics
1 answer:
AVprozaik [17]4 years ago
3 0

Answer:

ANSWER BELOW I

                             I

                            V

Remember that w=mg where w is weight in Newtons, m is mass in kilograms, and g is gravity in

m/s2

. For example, for Earth, 445 N = 45.4 × 9.8

m/s2

:Notice that the x-axis values will be gravity in

m/s2

, which is already given in the table, and the y-axis values will be the weight in Newtons. Remember to round your weights to a whole number, and to enter the points starting with the lowest gravity (moon, then Mars, then Venus, then Earth).

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A man pushes a 34 kg lawn mower using a handle inclined 45.0 ∘ from the horizontal. He pushes with 75 N directed along the handl
tresset_1 [31]

Answer:

333 N

Explanation:

The weight of an object is given by:

W=mg

where

m is the mass of the object

g is the acceleration of gravity

For the mower in the problem,

m = 34 kg

Also

g=9.8 m/s^2

So, the weight of the mower is

W=(34)(9.8)=333 N

6 0
3 years ago
The nucleus of the atom contains 8 protons and 9 neutrons. The atom is electrically
Alinara [238K]

Answer:

an atom has 8 electrons

Explanation:

3 0
3 years ago
If the truck has a mass of 2,500 kilograms , what is its momentum ? (V=45m/s) Express your amswer
vlabodo [156]

Answer:

The answer is 2,500 * 45 = 112500kgm/s

6 0
2 years ago
Two capacitors with capacitances of 1.0 m F and 0.50 m F, respectively, are connected in series. The system is connected to a 10
forsale [732]

Answer:

Therefore energy is stored in the 1.0 mF capacitor is 5.56×10⁻⁹ J

Explanation:

Series capacitor: The ending point of a capacitor is the starting point of other capacitor.

If C₁ and C₂ are connected in series then the equivalent  capacitance is C.

where     \frac{1}{C} =\frac{1}{C_1}+\frac{1}{C_2}

Given that,

C₁ = 1.0 mF=1.0×10⁻³F  and  C₂ = 0.50mF=0.50×10⁻³F  

If C is equivalent capacitance.

Then    \frac{1}{C} =\frac{1}{1.0}+\frac{1}{0.5}

\Rightarrow \frac{1}{C} =\frac{3}{1}

\Rightarrow C=\frac{1}{3} mF

Again given that the system is connected to a 100-v battery.

We know that

q=Cv

q= charge

C= capacitor

v= potential difference

Therefore

q=(\frac{1}{3} \times 10^{-3}\times10) C

 =\frac{10^{-2}}{3} C

The electrical potential energy stored in a capacitor can be expressed

U=\frac{q^2C}{2}

q= charge

c=capacitance of a capacitor

Therefore energy is stored in the 1.0 mF capacitor is

U=\frac{q^2C_1}{2}

\Rightarrow U=\frac{(\frac{10^{-2}}{3})^2\times 10^{-3} }{2}

\Rightarrow U= 5.56\times 10^{-9} J

 

8 0
3 years ago
Which of the following is the largest disadvantage of hydropower
kirill115 [55]
Hydro power, although a low-cost option, is not implemented every time because of the amount of disadvantages there are. One of the disadvantages this has is the pollution is gives. Since the reservoir is always filled with water, this causes any surrounding plants and trees to decompose, releasing a huge amount of methane and carbon dioxide into the environment. Aside from this, it also destroys nearby habitats, and diverts natural waterways, effectively killing fishes too.
6 0
3 years ago
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