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3 years ago

Vehicle emissions devices incorporate a chemical reaction to help control carbon monoxide pollution: 2CO+ O2->2CO2

Chemistry

2 answers:

Ahat [919]3 years ago

8 0

Answer: The correct answer is it converts carbon monoxide faster.

Explanation:

Catalyst is defined as the substance which increases the rate of the reaction without getting actually participated in the reaction. It can be easily regenerated at the end of the reaction.

For the given chemical reaction:

$2CO+O_2\rightarrow 2CO_2$

Addition of catalyst will lead us to the production of carbon dioxide faster or it may convert carbon monoxide faster into the products.

Hence, the correct answer is it converts carbon monoxide faster.

BigorU [14]3 years ago

3 0

It convert carbon monoxide faster

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4 years ago

concentrated sulfuric acid (H2SO4) has a concentration of 18.0 M. What volume of concentrated H2SO4 is needed to make 2.5 liters

olga2289 [7]

Answer:

$V_1=0.139L=139mL$

Explanation:

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3 years ago

Read 2 more answers

Which of the following would have the smallest ionization energy? S Р K Ca

goldenfox [79]

Answer:

Explanation:

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3 years ago

A photon with 2.3 eV of energy can eject an electron from potassium. What is the corresponding wavelength of this type of light?

Ira Lisetskai [31]

Answer:

$\lambda=540.16\ nm$

Explanation:

Given that:

The energy of the photon = 2.3 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.60 × 10⁻¹⁹ J

So, Energy = $2.3\times 1.60\times 10^{-19}\ J=3.68\times 10^{-19}\ J$

Considering

$Energy=\frac {h\times c}{\lambda}$

Where,

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

c is the speed of light having value $3\times 10^8\ m/s$

$\lambda$ is the wavelength of the light being bombarded

Thus,

$3.68\times 10^{-19}=\frac {6.626\times 10^{-34}\times 3\times 10^8}{\lambda}$

$\frac{3.68}{10^{19}}=\frac{19.878}{10^{26}\lambda}$

$3.68\times \:10^{26}\lambda=1.9878\times 10^{20}$

$\lambda=5.40163\times 10^{-7}\ m=540.16\times 10^{-9}\ m$

Also,

1 m = 10⁻⁹ nm

So,

$\lambda=540.16\ nm$

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Answer:

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