Vehicle emissions devices incorporate a chemical reaction to help control carbon monoxide pollution: 2CO+ O2->2CO2
2 answers:
<u>Answer:</u> The correct answer is it converts carbon monoxide faster.
<u>Explanation:</u>
Catalyst is defined as the substance which increases the rate of the reaction without getting actually participated in the reaction. It can be easily regenerated at the end of the reaction.
For the given chemical reaction:
Addition of catalyst will lead us to the production of carbon dioxide faster or it may convert carbon monoxide faster into the products.
Hence, the correct answer is it converts carbon monoxide faster.
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<u>Answer: </u>The equation which is wrong is
<u>Explanation:</u>
For the given reaction:
The expression for is given by:
The concentration of solids are taken to be 1, only concentration of gases and liquid states are taken. The pressure of only gases are taken.
Relationship between is given by the expression:
where,
= number of moles of gaseous products - number of moles of gaseous reactants
R = gas constant
T= temperature
For the above reaction,
= number of moles of gaseous products - number of moles of gaseous reactants = 0 - 3 = -3
Hence, the expression for is:
Therefore, the equation which is wrong is
Answer:
The equivalent weight of M is approximately 31.8 g
The equivalent weight of N is approximately 27.98 g
Explanation:
The given parameters are;
The percentage of the the metal M in in the chloride = 47.25%
Where by the chemical formula for the metal chloride is MClₓ, we have;
47.25% of the mass of MClₓ = Mass of M = W
Therefore, we have;
0.4725 × (W + 35.5·x) = W
0.4725·W + 0.4725×35.5×x = W
W - 0.4725·W = 16.77·x
0.5275·W = 16.77·x
W/x = 16.77/0.5275 = 31.799 = The equivalent weight of M
The equivalent weight of M = 31.799 ≈ 31.8 g
Given that 1 gram of M is displaced by 0.88 gram of N, then the equivalent weight of N that will displace 31.799 = 0.88 × 31.799 ≈ 27.98 g
The equivalent weight of N = 27.98 g.