A basketball is thrown straight up in the air. At its peak, it is 0.02 km high and has a velocity of 0 m/s. What is its final ve
1 answer:
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Answer:
Force constant will be 1195.85 N/m
Work done will be 1.6859 J
Explanation:
We have given the force, F = 63.5 N
Spring is stretched by 5.31 cm
So x = 0.0531 m
Force is given , F = 63.5 N
We know that force is given by
So
k = 1195.85 N/m
Now we have to find the work done
We know that work done is given by
Answer:
B) the change in momentum.
Explanation:
The impulse is defined as the product between the force applied on an object (F) and the duration of the collision ():
(1)
We can rewrite the force by using Newton's second law, as the product between mass (m) and acceleration (a):
So, (1) becomes
Now we can also rewrite the acceleration as ratio between the change in velocity and change in time: . If we substitute into the previous equation, we find
And the quantity is equivalent to the change in momentum,
.