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shepuryov [24]
4 years ago
8

A basketball is thrown straight up in the air. At its peak, it is 0.02 km high and has a velocity of 0 m/s. What is its final ve

locity when it hits the ground?
Physics
1 answer:
Aleks04 [339]4 years ago
7 0

Answer:

20 m/s

Explanation:

Given:

Δy = 0.02 km = 20 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: v

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (9.8 m/s²) (20 m)

v = 19.8 m/s

Rounded to one significant figure, the final velocity is 20 m/s towards the ground.

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A concrete highway is built of slabs 12 m long (20°C). How wide should the expansion cracks between the slabs be (at 20°C) to pr
Bezzdna [24]

Answer:

0.001152m

Explanation:

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Where ∆L is the change in length = L2-L1

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Substituting this values inside the formula to get the final length L2 after expansion, we have;

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