1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gwar [14]
3 years ago
14

How many grams of aluminum sulfate form when 3.90 grams of aluminum is placed in 13.65 grams of sulfuric acid?

Chemistry
2 answers:
SVETLANKA909090 [29]3 years ago
4 0

Answer:

Mass = 17.12 g

Explanation:

Given data:

Mass of Al = 3.90 g

Mass of H₂SO₄ = 13.65

Mass of aluminium sulfate = ?

Solution:

Chemical equation:

3H₂SO₄ + 2Al   →  Al₂(SO₄)₃ + 3H₂

Now we will calculate the number of moles of each reactant.

Moles of H₂SO₄:

Number of moles = mass/ molar mass

Number of moles = 13.65 g/ 98.079 g/mol

Number of moles = 0.14 mol

Moles of Al:

Number of moles = mass/ molar mass

Number of moles = 3.90 g/ 27 g/mol

Number of moles = 0.14 mol

Now we will compare the moles of aluminium sulfate with sulfuric acid and aluminium.

                           H₂SO₄       :         Al₂(SO₄)₃

                               3            :              1

                           0.14            :          1/3×0.14 = 0.05

                              Al            :           Al₂(SO₄)₃

                               2            :             1

                            0.14           :        1/2×0.14 = 0.07

The number of moles of aluminium sulfate produced by sulfuric acid are less so it will limiting reactant and limit the amount of aluminium sulfate.

Mass of aluminium sulfate:

Mass = number of moles × molar mass

Mass = 0.05 mol × 342.15 g/mol

Mass = 17.12 g

blondinia [14]3 years ago
3 0

17.1g

Explanation:

Mass of aluminium = 3.9g

Mass of sulfuric acid = 13.65g

Unknown:

Mass of aluminium sulfate = ?

Solution:

To solve this problem, we need to:

   Convert the mass to moles

   Find the limiting reagent

The limiting reagent is the one in short supply in the reaction. It is important to delineate this reagent because it determines the extent of the reaction.

Also, it is important to obtain the balanced reaction equation:

    2Al    +     3H₂SO₄     →      Al₂(SO₄)₃    +   3 H₂

Number of moles = \frac{mass}{molar mass}

  molar mass of Al = 27g/mol

                      H₂SO₄ = 2(1) + 32 + 4(16) = 98g/mol

Number of moles of Al = \frac{3.9}{27} = 0.14mole

Number of moles of H₂SO₄ = \frac{13.65}{98} = 0.14mole

   2 mole of Al reacts with 3 mole of sulfuric acid

   0.14 mole of Al will react with \frac{0.14 x 3}{2} =  0.21mole

      but the amount of sulfuric acid given is 0.14 mole this suggest the sulfuric acid is in short supply. It is the limiting reagent.

To find the number of mole of aluminium sulfate;

             3 mole of sulfuric acid will produce 1 mole of the sulfate

             0.14 mole of the sulfuric acid will produce \frac{0.14}{3} = 0.05mole

Mass of the sulfate = number of moles x molar mass

molar mass of  Al₂(SO₄)₃ = 2(27) + 3(32 + 4(16)) = 342g/mole

 Mass = 0.05 x 342 = 17.1g

learn more:

Molar mass brainly.com/question/2861244

#learnwithBrainly

You might be interested in
At the beach, Kim noticed that breezes blew from the ocean to the land during the day and from the land to the ocean at night. W
Cloud [144]
Sea breeze the other person is a hundred percent write
5 0
3 years ago
Read 2 more answers
What is white light?
PSYCHO15rus [73]

White light is when red, orange, and yellow are absorbed.

8 0
2 years ago
375ml of a 0.455m sodium chloride solution is dilluted with 1.88l of water. what is the new concentration in molarity
mestny [16]
0.375 L of the NaCl solution contains 0.455 moles  (1)

            since it was diluted to 1.88 L

then let   1.88 L of solution contain  x  moles  (2)

            by combining both (1) and (2)      
       
        ⇒     (0.345 L) x = (0.455 mol) (1.88 L)

       ⇒                     x = (0.242 mol · L)  ÷ (0.345 L)

       ⇒                     x =  0.702 mol

                
Thus the molarity of the NaCl after being diluted is 0.702 M  OR 0.702 mol / L   OR  0.702 mol/dm³. 
7 0
4 years ago
Read 2 more answers
Is it possible for an object not to be in motion and still have force acting upon it?
RSB [31]
Yes,this is an example:
An apple is sitting on a desk he is not in motion but one of the forces acting upon it is gravitational pull because is not floating around, the earth gravitational pull is pulling it down to the earth's surface.

3 0
3 years ago
The theoretical yield for CuCO3.Cu(OH)2+2h2SO4 ®2CuSO4+2H2O+3CO2
olga nikolaevna [1]

Answer:

bxnhdjxjdjvxjsj sbdhhxhchdbd

5 0
3 years ago
Other questions:
  • Which of the following is a common groundwater contaminant?
    6·2 answers
  • The physical state in which a substance has a no definite volume is:
    6·1 answer
  • What determines the average kinetic energy of particles in a gas ?
    15·2 answers
  • The density of a 22.0% by mass ethylene glycol (c2h6o2) solution in water is 1.04 g/ml . part a find the molarity of the solutio
    13·1 answer
  • Which of the following amino acids have more than one asymmetric center?
    13·1 answer
  • How many moles of NO3 are there in 6.2g?
    9·2 answers
  • I need to know what a metal nonmetel and metalloid
    13·2 answers
  • Why was it possible to neutralize HCI using NaOH?
    6·1 answer
  • What is the molar mass for Mn3O4?
    9·1 answer
  • Photosynthesis needs water and carbon dioxide to happen. These 2 ingredients are called _______.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!