All categories

3 years ago

Give an example where instantaneous speed is different from average speed

2 answers:

6 0

The speedometer of a car reveals information about the instantaneous speed of your car.
It shows your speed at a particular instance in time...
Yet, on average, you were moving with a speed of 25 miles per hour.

Hope you liked the example, and glad I could help!

Brut [27]3 years ago

6 0

Answer:

Yes average speed may be different from instantaneous speed

Explanation:

When an object is moving with non uniform speed on a straight road or on a curved path then its instantaneous speed at different points of its path is different.

But if we will find the average speed of the path then it will be different from its actual average speed

For example we can say that let a Car is moving for speed 40 km/h for first hour of its journey and then for next hour of its journey its speed is 60 km/h

So here instantaneous speed of the car is either 40 km/h or 60 km/h

While to find the average speed we will say

$v_{avg} = \frac{v_1 + v_2}{2}$

$v_{avg} = \frac{40 + 60}{2} = 50 km/h$

You might be interested in

7. You start to walk toward the east towards home at a constant speed of 4 km/hr. At the same time, Someone else leaves your hom

amm1812

A) position time graph for both is shown

here one of the graph is of lesser slope which means it is moving with less speed while other have larger slope which shows larger speed

At one point they intersects which is the point where they both will meet

B) Let the two will meet after time "t"

now we can say that

if they both will meet after time "t"

then the total distance moved by you and other person will be same as the distance between you and home

so it is given as

$v_1t + v_2t = d$

$4*t + 28*t = 3.2 km$

$t = \frac{3.2}{32} = 0.1 hr$

so they will meet after t = 6 min

so from position time graph we can see that two will meet after t = 6 min where at this position two graphs will intersect

4 0

3 years ago

⚠️ PLEASE HELP ⚠️

Svetllana [295]

Answer:

-79.6

-80

-81.2

Explanation:

5 0

3 years ago

Read 2 more answers

Consider a uniform horizontal wooden board that acts as a pedestrian bridge. The bridge has a mass of 300 kg and a length of 10

gayaneshka [121]

Answer:

F = 2123.33N

Explanation:

In order to calculate the torque applied by the left support, you take into account that the system is at equilibrium. Then, the resultant of the implied torques are zero.

$\Sigma \tau=0$

Next, you calculate the resultant of the torques around the right support, by taking into account that the torques are generated by the center of mass of the wooden, the person and the left support. Furthermore, you take into account that torques in a clockwise direction are negative and in counterclockwise are positive.

Then, you obtain the following formula:

$-\tau_l+\tau_p+\tau_{cm}=0$ (1)

τl: torque produced by the left support

τp: torque produced by the person

τcm: torque produced by the center of mass of the wooden

The torque is given by:

$\tau=Fd$ (2)

F: force applied

d: distance to the pivot of the torque, in this case, distance to the right support.

You replace the equation (2) into the equation (1) and take into account that the force applied by the person and the center of mass of the wood are the their weight:

$-Fd_1+W_pd_2+W_{cm}d_3=0\\\\d_1=6.0m\\\\d_2=2.0m\\\\d_3=3.0m\\\\W_p=(200kg)(9.8m/s^2)=1960N\\\\W_{cm}=(300kg)(9.8m/s^2)=2940N$

Where d1, d2 and d3 are distance to the right support.

You solve the equation for F and replace the values of the other parameters:

$F=\frac{W_pd_2+W_d_3}{d_1}=\frac{(1960N)(2.0m)+(2940N)(3.0m)}{6.0m}\\\\F=2123.33N$

The force applied by the left support is 2123.33 N

8 0

3 years ago

Magnesium hydroxide is used in? soap batteries antacids detergents

Inga [223]

The answer is antacids

3 0

3 years ago

Read 2 more answers

Why is current a scalar quantity?

Nutka1998 [239]

Despite current has a magnitude and a direction, like vectors, it is a scalar because it doesn't obey laws of vector addition. For instance, if we consider a junction of $90^{\circ}$ in a circuit, and two currents entering this junction, we know that the resultant current is just the algebraic sum of the two currents, not the vector sum, so it is not a vector quantity.

5 0

3 years ago