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antiseptic1488 [7]
3 years ago
8

Give an example where instantaneous speed is different from average speed

Physics
2 answers:
Ulleksa [173]3 years ago
6 0
The speedometer of a car reveals information about the instantaneous speed of your car.
It shows your speed at a particular instance in time...
Yet, on average, you were moving with a speed of 25 miles per hour.

Hope you liked the example, and glad I could help!
Brut [27]3 years ago
6 0

Answer:

Yes average speed may be different from instantaneous speed

Explanation:

When an object is moving with non uniform speed on a straight road or on a curved path then its instantaneous speed at different points of its path is different.

But if we will find the average speed of the path then it will be different from its actual average speed

For example we can say that let a Car is moving for speed 40 km/h for first hour of its journey and then for next hour of its journey its speed is 60 km/h

So here instantaneous speed of the car is either 40 km/h or 60 km/h

While to find the average speed we will say

v_{avg} = \frac{v_1 + v_2}{2}

v_{avg} = \frac{40 + 60}{2} = 50 km/h

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At the top of a giant swing on the gymnastics high bar, candy's velocity is 1 m/s, and she is 3.5 m high. if candy's mass is 50
Allushta [10]
The total mechanical energy is the sum of the kinetic energy and the gravitational potential energy:
E=K+U= \frac{1}{2}mv^2 +mgh
where m=3.5 kg is Candy's mass, v=1 m/s is her velocity and h=3.5 m is her height. If we replace these numbers, we find the mechanical energy of the system:
E= \frac{1}{2} (50 kg)(1m/s)^2 + (50 kg)(9.81 m/s^2)(3.5 m)=1742 J =1.74 kJ
6 0
3 years ago
An unlit match is held near (not touching) a Bunsen flame. The match doesn't get hot enough to light because
ohaa [14]
The answer is option D)
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option A) also sounds correct, but it isn't. this is because the flame IS hot enough to burn the match stick, it's just that the match stick is positioned the wrong way
6 0
3 years ago
Two tougboats are toeing a ship each exerts a force of 6000N and the angle between the two ropes is 60 calculate the resultant f
Arlecino [84]

Answer:

10392.30N

Explanation:

We proceed by computing the individual force exerted by the boats

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Hence

Force = F cos θ

F=6000 cos 30

F=6000*0.866

F=5196.15 N

Since the boats are two and also at the same angle and also exerting the same force

The Net force = 2*5196.15

Net force=10392.30N

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