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ololo11 [35]
3 years ago
11

A small file or organization use a payroll program for calculating staff wages each month each employee has a unique payroll num

ber had is paid a fixed hourly rate which may be different for different employee. the system uses a master file containing long term details such as name Address, hourly,rate of pay and total pay for a year .the key field in the master file is the payroll number and the filled is stored in this field .each month by each a transaction file is produced containing details of the hours worked during that month by each employee,(a)state the type of processing used in this application and explain why this type of processing is suctable,(b) describe the processing take place each month when the payroll program is run staff with unsorted transaction file and end after the master file has been updated the pay slips have been printed,(c) explain what would happen during the processing of an employee payroll number had been entered incorrectly into the transaction file​
Chemistry
1 answer:
Rama09 [41]3 years ago
8 0

Answer:

the company is now aarav and its CEO of samruddhi and is the CEO in meeting with holika and will come in to help with holika as brainlyiest as the company's chief financial adviser to solve di problems

Explanation:

it was the most common thing that happened in my first pregnancy in my first year and I m and the other girl Bo.. were pretty good vibes for the last day of samruddhi but they are still very much a many years after I was knowing that

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2 years ago
Substitute natural gas (SNG) is a gaseous mixture containing CH4(g) that can be used as a fuel. One reaction for the production
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Answer:

ΔH° of the reaction is -747.54kJ

Explanation:

Based on gas law, it is possible to find the ΔH of a reaction using ΔH of half reactions.

Using the reactions:

<em>(1) </em>C(graphite) + 1/2O₂(g) → CO(g) ΔH° = -110.5 kJ

<em>(2) </em>CO(g) + 1/2O₂(g) → CO₂(g) ΔH° = -283.0 kJ

<em>(3) </em>H₂(g) + 1/2O₂(g) → H₂O(l) ΔH° = -285.8 kJ

<em>(4) </em>C(graphite) + 2H₂(g) → CH₄(g) ΔH° = -74.81 kJ

<em>(5) </em>CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) ΔH° = -890.3 kJ

The sum of 4×(4) + (5) gives:

4C(graphite) + 8H₂(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) + 3CH₄(g)

ΔH° = -74.81 kJ ×4 - 890.3 kJ = -1189.54kJ

Now, this reaction - 4×(1) gives:

4CO(g) + 8H₂(g) → CO₂(g) + 2H₂O(l) + 3CH₄(g)

ΔH° = -1189.54kJ - 4×-110.5 = <em>-747.54kJ</em>

<em></em>

Thus <em>ΔH° of the reaction is -747.54kJ</em>

3 0
3 years ago
Why are the transition metals not isoelectronic with noble gas atoms?
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The atoms and ions that have the similar electron configuration are named isoelectronic. The common ions of representative elements are isoelectronic with a noble gas. When forming ions, transition metals be unable to find their valence s-sublevel electrons before they lose their d-sub level electrons.
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Answer:

B. Below the equilibrium price

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