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belka [17]
3 years ago
10

at a parade, 1/4 of the participants have red hair, 1/6 of them have brown hair and the rest of them have black hair. which frac

tion of the participants have black hair?
Mathematics
1 answer:
netineya [11]3 years ago
6 0
\frac{1}{1}-\ all\ participants\\\\
\frac{1}{4}-\ participants\ with\ red\ hair\\\\ \frac{1}{6}-\ participants\ with\ brown\ hair\\\\
participants\ ith\ black\ hair=1-\frac{1}{4}-\frac{1}{6}\ \ \ | mu;tiply\ by\ 12\\\\
12participants\ ith\ black\ hair=12-3-2\\\\
12participants\ ith\ black\ hair=7\ \ \ \ | divide\ by\ 12\\\\
participants\ ith\ black\ hair=\frac{7}{12}
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DochEvi [55]

Answer:

y - 3 = (2/5)(x + 2)

Step-by-step explanation:

Start with the general point-slope form of the equation of a straight line:

y - k = m(x - h).  Now substitute -2 for h and 3 for k, and also 2/5 for m:

y - 3 = (2/5)(x + 2)

5 0
2 years ago
For f(x) = 3x +1 and g(x) = x2 – 6, find (f- g)(x).
Fiesta28 [93]

Answer:

\boxed{\sf (f-g)(x) = -{x}^{2}  + 3x + 7}

Given:

\sf f(x) = 3x + 1 \\ \sf g(x) =  {x}^{2}  - 6

To find:

\sf (f - g)(x) = f(x) - g(x)

Step-by-step explanation:

\sf \implies(f - g)x = f(x) - g(x) \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = (3x + 1) - ( {x}^{2}  - 6) \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = (3x + 1)  + (-  {x}^{2}  + 6) \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = 3x + 1 -  {x}^{2}  + 6 \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = - {x}^{2}  + 3x + 1 + 6 \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    =  -{x}^{2}  + 3x + 7

8 0
3 years ago
HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!
AleksAgata [21]
Your answer would be b.2 

6 0
2 years ago
Read 2 more answers
Can someone help me with this? please<br><br>alguien me puede ayudar con esto? porfavorr
soldi70 [24.7K]

See attachment for the number line that compares the numbers 5.3, 5 1/5 and 5

<h3>How to plot the numbers on the number line?</h3>

The numbers are given as:

5.3, 5 1/5 and 5

We start by representing the numbers as decimals (i.e. real numbers).

So, we have:

5.3, 5.2 and 5

Reorder the numbers in ascending number (i.e. from least to greatest)

So, we have

5, 5.2 and 5.3

Next, we plot the numbers on a number line using a scale of 0.1

This can be visualized as

5        5.2      5.3

See attachment for the number line that compares the numbers 5.3, 5 1/5 and 5

Read more about number line at

brainly.com/question/24644930

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8 0
1 year ago
A drug is eliminated from the body through urine. Suppose that for a dose of 10 milligrams, the amount A(t) remaining in the bod
adell [148]

Answer: a - 4.512 hours

b - 1.94 hours

Step-by-step explanation:

Given,

a) A(t) = 10 (0.7)^t

To determine when 2mg is left in the body

We would have,

A(t) = 2, therefore

2 = 10(0.7)^t

0.7^t =2÷10

0.7^t = 0.2

Take the log of both sides,

Log (0.7)^t = log 0.2

t log 0.7 = log 0.2

t = log 0.2/ 0.7

t = 4.512 hours

Thus it will take 4.512 hours for 2mg to be left in the body.

b) Half life

Let A(t) = 1/2 A(0)

Thus,

1/2 A(0) = A(0)0.7^t

Divide both sides by A(0)

1/2 = 0.7^t

0.7^t = 0.5

Take log of both sides

Log 0.7^t = log 0.5

t log 0.7 = log 0.5

t = log 0.5/log 0.7

t = 1.94 hours

Therefore, the half life of the drug is 1.94 hours

6 0
3 years ago
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