For a relative frequency distribution, relative frequency is computed is computed as ____________.
1 answer:
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The resultant force on the box is C) 10 Newtons to the left.
Explanation:
The figure of the problem is attached.
We see that there are two forces acting on the box along the horizontal direction:
- A force of 10 N acting to the right
- A force of 20 N acting to the left
By taking "to the right" as positive direction, we can rewrite the two forces as follows:
Where the second force is negative since it acts to the left.
Since the two forces are in line, we can find their resultant simply by calculating their algebraic sum. By doing so, we find:
And the negative sign tells us that the direction is to the left.
Therefore, the correct answer is
C) 10 Newtons to the left.
Learn more about forces here:
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E1 reaction works in the mechanism that the removal of an HX substituent results in the formation of a double bond. The E1 reaction for 2-methylbutan-2-ol is shown in the figure. This reaction is called acid-catalyzed dehydration of a tertiary alcohol.
The mechanism works in three major steps:
1. The OH group of the main reactant is hydrated by H2SO4 so it becomes H2O.
2. The H2O leaves taking electrons with it. This results to a carbocation intermediate on the carbon atom where it was attached.
3. Another H2O protonates the beta carbon. This is the carbon atom next to the carbocation. It will donate its electrons to the neighboring C-C bond, as indicated by the arrow. The carbons are rehybridized from sp3 to sp2, which is a pi bond. As a result, a double bond forms.
The product is 2-methyl-2-butene.
The mechanism works in three major steps:
1. The OH group of the main reactant is hydrated by H2SO4 so it becomes H2O.
2. The H2O leaves taking electrons with it. This results to a carbocation intermediate on the carbon atom where it was attached.
3. Another H2O protonates the beta carbon. This is the carbon atom next to the carbocation. It will donate its electrons to the neighboring C-C bond, as indicated by the arrow. The carbons are rehybridized from sp3 to sp2, which is a pi bond. As a result, a double bond forms.
The product is 2-methyl-2-butene.