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Trava [24]
2 years ago
10

Which products would form if chlorine gas was bubbled through a solution of sodium bromide?

Chemistry
2 answers:
pickupchik [31]2 years ago
8 0

Answer:

NaCl and Br2

Explanation:

Edge 2020

777dan777 [17]2 years ago
4 0

Answer:

i think d

Explanation:

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What type of reaction occurs between aqueous ammonia solution and an acid?
gizmo_the_mogwai [7]
Neutralization reaction.
8 0
3 years ago
Read 2 more answers
How many molecules are in 34.7 grams of water?
Anika [276]

Answer:

This part require data such as Avogadro's number and the molar mass of water. But first, let's find the mass of water in the specified volume by making use of the density formula:

Density = mass/volume

1 g/mL = Mass/70 mL

Mass = 70 g

Each water contains 18 grams per mole, and each mole contains 6.022×10²³ molecules of water. Thus,

70 g * 1mole/18 g * 6.022×10²³ molecules/mole = 2.342×10²⁴ molecules of water

Explanation:

8 0
2 years ago
How many grams of sodium bicarbonate are needed to completely react with a 0.892 m phosphoric acid solution that contains to 45.
SVETLANKA909090 [29]

Answer:

umm idk if I was right or not

7 0
3 years ago
What is 165 lb in kilograms (kg)?<br> 1 kg = 2.20 lb<br> (please show work) ASAP
Slav-nsk [51]
165 Pounds (lbs) = 74.84 Kilograms (kg)
1 lbs = 0.453592 kg 1 kg = 2.204623 lbs
5 0
3 years ago
Calculate the volume in liters of a 2.3*10^-6 mercury(I) chloride solution that contains of mercury(I) chloride . Round your ans
GalinKa [24]

Answer:

2.00x10⁵L

Explanation:

<em>...That contains 125g of mercury(I) chloride...</em>

<em />

The molarity, M, of a solution represents the moles of solute (Mercury(I) chloride), per liter of solution.

To solve this question, we need to determine the moles of mercury(I) chloride present in 125g. Then, with molarity, we can find the volume of the solution:

<em>Moles Mercury(I) chloride -Molar mass: 271.52g/mol-:</em>

125g * (1mol / 271.52g) = 0.460 moles

<em>Volume:</em>

0.460 moles * (1L / 2.3x10⁻⁶mol) =

<h3>2.00x10⁵L</h3>
6 0
2 years ago
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