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3 years ago

What information is needed to determine the energy of an electron in a many-electron atom? a) n. b) l. c) ml. d)ms

Chemistry

2 answers:

mel-nik [20]3 years ago

8 0

Answer:

The correct answer is b.

Explanation:

The quantum number n specifies the energetic level of the orbital, the first level being the one with the least energy. As n increases, the probability of finding the electron near the nucleus decreases and the orbital energy increases.

In the case of atoms with more than one electron, the quantum number l also determines the sublevel of energy in which an orbital is found, within a certain energy level. The value of l is designated by the letters s, p, d, and f.

Have a nice day!

Masteriza [31]3 years ago

5 0

The principal quantum number (n) is needed to determine the energy of an electron in a many-electron atom

<h3>Further explanation</h3>

In an atom, there are energy levels in the shell and sub shell.

This energy level is expressed in terms of electron configurations.

Writing the electron configuration starts from the lowest to the highest subshell's energy level. There are 4 sub-shells in an atom's shell, namely s, p, d, and f.

Each sub-shell also has orbitals drawn in the form of a square box in which there are electrons symbolized by half arrows.

Each orbital in an atom consists of 4 quantum numbers

n is the principal quantum number ---> describes the size of the orbitals

l is the angular momentum / azimuthal quantum number -> describes the shape of the orbitals.

ml, the magnetic quantum number -> describes the orientation of orbitals in space

ms, the electron-spin quantum number ---> describes the spin of electrons

Value of n: positive integer

value of l: s = 0, p = 1, d = 2, f = 3, ... (n-1)

ml value: between -l to + l

ms value: +1/2 or -1/2

The energy of the electrons is indicated by the value of n, because electrons can move between the shell by releasing energy or absorbing energy. the greater the value of n, the greater the electron energy . The Value of n = 1 is the lowest energy level

So the correct answer is a)n

<h3>Learn more </h3>

electron transitions

brainly.com/question/2079874

the locations and properties of two electrons

brainly.com/question/2292596

It's sublevel

brainly.com/question/4520082

a possible full set of quantum numbers

brainly.com/question/5389767

Keywords: orbitals, subshells, quantum numbers

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A mixture containing 20 mole % butane, 35 mole % pentane and rest

notka56 [123]

Answer:

2.5 % butane, 42.2 % pentane and 55.3 % hexane

Explanation:

Hello,

In this case, the mass balance for each substance is given by:

$Butane:z_bF=y_bD+x_bB\\\\Pentane: z_pF=y_pD+x_pB\\\\Hexane: z_hF=y_hD+x_hB$

Whereas $y$ accounts for the fractions at the outlet distillate and $x$ for the fractions at the outlet bottoms. Moreover, with the 90 % recovery of butane, we can write:

$0.9=\frac{y_bD}{z_bF}$

So we can compute the product of the molar fraction of butane at the distillate by total distillate flow by assuming a 100-mol feed:

$y_bD=0.9*z_bF=0.9*0.2*100mol=18mol$

The total distillate flow:

$y_bD=18mol\\\\D=\frac{18mol}{0.95} =18.95mol$

And the total bottoms flow:

$F=D+B\\\\B=F-D=100mol-18.95mol=81.05mol$

Next, by using the mass balance of butane, we compute the molar fraction of butane at the bottoms:

$x_b=\frac{z_bF-y_bD}{B} =\frac{0.2*100mol-18mol}{81.05} =0.025$

Then, the molar fraction of pentane and hexane:

$x_p=\frac{z_pF-y_pD}{B} =\frac{0.35*100mol-0.04*18.95mol}{81.05} =0.422$

$x_h=\frac{z_hF-y_hD}{B} =\frac{(1-0.2-0.35)*100mol-(1-0.95-0.04)*18.95mol}{81.05} =0.553$

Therefore, the molar composition of the bottom product is 2.5 % butane, 42.2 % pentane and 55.3 % hexane.

NOTE: notice the result is independent of the value of the assumed feed, it means that no matter the basis, the compositions will be the same for the same recovery of butane at the feed, only the flows will change.

Regards.

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