<span>It does not matter how heavy the object is, as long as there is no drag or wind interference (such as wind on a feather or piece of paper) the gravitational pull will be equal, therefore the answer is 9s.</span>
The energy carried by the incident light is
where h is the Planck constant and f is the frequency of the light. The threshold frequency is the frequency that corresponds to the minimum energy needed to eject the electrons from the metal, so if we substitute the threshold frequency in the formula, we get the minimum energy the light must have to eject the electrons:
Answer:
P = 227 N
Explanation:
Assuming the crate is on horizontal ground and subject to a horizontal force.
F = ma
P - μmg = ma
P = m(a + μg)
P = m(v²/2s + μg)
P = 50(4²/(2(5))+ 0.3(9.8))
P = 227 N
To solve this problem we need to consider the concept about Ampere's Law.
The Ampere's law say that,
Where,
F= Mangetic field
Permeability of free space
I =current
R= Radius from the wire in meters.
A) At the first case the force on wire is repulsive, replacing our values
In repulsive direction.
B) At the second case de Force flow in the same direction, then we have,
In attractive direction