Explanation:
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Fnet=m*a
a= Fnet/m
a=(20N[E]+9.0N[E])/ 12.0kg
a=2.4167m/s^2
a ≈ 2.4m/s^2
Answer:
This above a triangle that models our situation.
Explanation:
We have a two componens., since we have a western componet and southern component. One travel in a southern direction. and the other travel in the west.
Let the component that travel in the south be the length of a.
According to the problem, the westard component is half of that so let that length be a/2.
Now we must find the angle of the wind in the South.
This means that what is angle that is opposite of the western componet because that angle is the most southward angle. So know we apply the tan property.

Our side opposite of the angle we trying to find is the western component and the side adjacent to it is the southern component. Also remeber since western and Southern negative displacements, we have


Now we take the arctan or inverse tan of 1/2.

Answer:
v_average = 15 m / s
Explanation:
The average speed can be found in two ways,
* taking the distance traveled and divide it by the time spent
* taking the velocities in each time interval and then finding the weighted average by the time fraction
v_average = 1 / t_total ∑
vi ti
Let's apply this last equation
Total time is
t = t₁ + t₂
t = 10 + 10 = 20 min
v_average = 10/20 10 + 10/20 20
v_average = 10/2 + 20/2
v_average = 15 m / s