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3 years ago

A solar eclipse will occur Group of answer choices

Physics

1 answer:

myrzilka [38]3 years ago

7 0

Answer:

3. at new Moon only when the Moon is on the ecliptic.

Explanation:

Solar eclipse is the condition when the moon comes in between the sun and the earth. In this condition the moon casts its shadow on the earth.

Whether the eclipse is a total solar eclipse, a partial solar eclipse or an annular solar eclipse depends on various factors, but the position of the moon must be on the same orbital plane as that of the earth's orbit around the sun.

The sun is about 400 times larger than the moon in size and the sun is almost 400 times farther from the earth than the moon is, this makes it possible for the moon to cover the sun completely leading to a complete solar eclipse.

As we know that the orbit of the earth around the sun and the orbit of the moon around the earth is elliptical which leads to a variation in the distance from their rotating centers, so not of every eclipse the moon covers the sun completely developing an annular eclipse.

When the moon is close enough to the earth on the ecliptic but not completely aligned in between the sun and the earth leads to a partial solar eclipse.

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A submarine can detect an approaching enemy submarine using sonar. If a stationary submerged submarine emits a 100kHz tone and r

prisoha [69]

Answer:

B ) 1.5 m/s

Explanation:

For the apparent frequency reflected by enemy submarine , the Doppler effect formula is

F = F₀ ( V + v) / (V - v)

F anf F₀ are real and apparent frequency , V and v are velocity of sound and velocity of enemy submarine respectively.

ΔF / F₀ = $\frac{2\times v}{V -v}$

Put ΔF = 200; F₀ = 100000 and V = 1482

200 / 100000 = $\frac{2\times v }{1482-v}$

v = 1.5 m s⁻¹ .

8 0

4 years ago

Two Earth satellites, A and B, each of mass m = 940 kg , are launched into circular orbits around the Earth's center. Satellite

-Dominant- [34]

Answer:

The required work done is $6.5\times10^{9}\ J$

Explanation:

Given that,

Mass of each satellites = 940 kg

Altitude of A = 4500 km

Altitude of B = 11100 km

We need to calculate the potential energy

Using formula of potential

$U_{A}=-\dfrac{Gm_{A}m_{E}}{r_{A}}$

Put the value into the formula

$U_{A}=-\dfrac{6.67\times10^{-11}\times940\times5.98\times10^{24}}{6.38\times10^{6}+4.50\times10^{6}}$

$U_{A}=-3.44\times10^{10}\ J$

We need to calculate the potential energy

Using formula of potential

$U_{B}=-\dfrac{Gm_{B}m_{E}}{r_{A}}$

Put the value into the formula

$U_{B}=-\dfrac{6.67\times10^{-11}\times940\times5.98\times10^{24}}{6.38\times10^{6}+11.10\times10^{6}}$

$U_{B}=-2.14\times10^{10}\ J$

We need to calculate the value of $k_{A}$

Using formula of $k_{A}$

$k_{A}=-\dfrac{1}{2}U_{A}$

Put the value into the formula

$k_{A}=\dfrac{1}{2}\times3.44\times10^{10}$

$k_{A}=1.72\times10^{10}\ J$

We need to calculate the value of $k_{B}$

Using formula of $k_{B}$

$k_{B}=-\dfrac{1}{2}U_{B}$

Put the value into the formula

$k_{B}=\dfrac{1}{2}\times2.14\times10^{10}$

$k_{B}=1.07\times10^{10}\ J$

We need to calculate the work done

Using formula of work done

$W=\Delta K+\Delta U$

$W=(k_{B}-k_{A})+(U_{B}-U_{A})$

$W=(-\dfrac{U_{B}}{2}+\dfrac{U_{A}}{2})+(U_{B}-U_{A})$

$W=\dfrac{1}{2}(U_{B}-U_{A})$

Put the value into the formula

$W=\dfrac{1}{2}\times(-2.14\times10^{10}+3.44\times10^{10})$

$W=6.5\times10^{9}\ J$

Hence, The required work done is $6.5\times10^{9}\ J$

7 0

3 years ago

two objects of equal mass are a fixed distance apart. if you halve the mass of each object which of the following is most likely

strojnjashka [21]

Answer:

A) half the original force

5 0

3 years ago

If a resultant vector is 12 m/s and the horizontal component is 9 m/s, what is the value of the vertical component? A. 5.8 m/s B

horrorfan [7]

The vertical component is B) 7.9 m/s

Explanation:

A vector can be resolved into its horizontal and vertical components. The horizontal and the vertical components form the sides of a right triangle, in which the resultant corresponds to the hypothenuse, so we can use Pythagorean's theorem:

$R=\sqrt{R_x^2+R_y^2}$

where

R is the resultant vector

Rx is the horizontal component

Ry is the vertical component

In this problem, we have:

R = 12 m/s is the resultant vector

Rx = 9 m/s is the horizontal component

Solving the formula for Ry, we find the vertical component:

$R_y = \sqrt{R^2-R_x^2}=\sqrt{12^2-9^2}=7.9 m/s$

Learn more about vector components:

brainly.com/question/2678571

#LearnwithBrainly

3 0

3 years ago

What is the angle θ between vectors A⃗ and B⃗ if A⃗ =4ı^−4ȷ^ and B⃗ =−5ı^+7ȷ^?

ololo11 [35]

The characteristics of the scalar product allows to find the angle between the two vectors is:

The angle θ = 170º

The scalar product is the product between two vectors whose result is a scalar.

A . B = |A| |B| cos θ

Where A and B are the vectors, |A| and |B| are the modules of the vectors and θ at the angle between them.

The vector is given in Cartesian coordinates and the unit vectors in these coordinates are perpendicular.

i.i = j.j = 1

i.j = 0

A . B = (4 i - 4j). * -5 i + 7j)

A . B = - 4 5 - 4 7

A. B = -48

We look for the modulus of each vector.

|A| = $\sqrt{x^2 +y^2 }$

|A| = $\sqrt{4^2 + 4^2}$

|A| = 4 √2

|B| = $\sqrt{5^2 +7^2}$

|B| = 8.60

We substitute.

-48 = 4√2 8.60 cos θ

-48 = 48.66 cos θ

θ = cos⁻¹ $\frac{-48}{48.664}$

θ = 170º

In conclusion using the dot product we can find the angle between the two vectors is:

the angle θ = 170º

Learn more about the scalar product here: brainly.com/question/1550649

8 0

3 years ago