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tino4ka555 [31]
3 years ago
13

How much smaller is an atom than a speck of dust

Physics
1 answer:
IceJOKER [234]3 years ago
3 0

Answer:

an atom is about a trillion times smaller then a speck of dust.

Explanation:

hope this helps :)

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An object is moving in the absence of a net force. Which of the following best describes the object's motion? -please help?
Gelneren [198K]
You can solve this by using Newton's First Law or Newton's Second Law.

1) Newton's First Law or Inertia Law states that in the abscense of a net force acting over an object, this will not chage its state of movement, i.e it will  remain at rest (if it is no moving) or with uniform movement (if the object is moving).

2) Newton's Second Law: Net force = mass * acceleration => acceleration = net force / mass = 0 / mass = 0.

Zero accelerations means rest or uniform movement.

First Law is implicit in Second Law.
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2 years ago
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List three advantages of reflecting telescopes over refracting telescopes.
Dima020 [189]

Answer:

Three advantages of Reflecting Telescope over refracting Telescope:

1. there is no chromatic aberration in the Reflecting Telescope being mirror as an objective, while Refracting Telescope can suffer chromatic aberration being using lenses.

2. image of Reflecting Telescope is brighter due to large, polished curved mirrors than Refracting Telescope

3. Reflecting Telescope is compact and portable in size than Refracting Telescope.

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3 years ago
PLEASE HELP WILL MARK BRAINLIEST AND GIVE LOTS OF POINTS
Aloiza [94]
23.  500x10=5,000 joules
24.  500x5=2,500 joules
25. 2,500 joules at point B
 
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2 years ago
Describe how a wheel and axle work?
andrezito [222]

A weally works when you pull something and a axle is something that you can push

Explanation:

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Calculate the gravitational potential energy of the interacting pair of the Earth and a 4 kg block sitting on the surface of the
STALIN [3.7K]

Answer:

- 2.425 x 10^5 J

Explanation:

The gravitational potential energy between earth and the bock is given by

U=-G\frac{Mm}{r}

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r be the radius of earth = 6380 km = 6380 x 10^3 m

by substituting the values in the above expression, we get

U=-6.67\times10^{-11}\frac{5.8\times 10^{24}\times 4}{6380\times 10^{3}}

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2 years ago
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