(0.053) (0.578) Multiply the numbers

Carrie runs 11.5 miles and five hours at a study pi runs 11.5 miles in five hours at a steady pace how long does it take her to

alukav5142 [94]

dividing 11.5 by 5 gives you the unit rate, then you just multiply that answer by 2 and you should be okay

8 0

3 years ago

Find the area of the composite figure.

Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

According to the Figure Given:

Total Horizontal Distance = 14 in

Length = 6 in

To Find :

The Area of the composite figure

Solution:

Firstly we need to find the area of Rectangular part.

So We know that,

$\boxed{ \rm \: Area \: of \: Rectangle = Length×Breadth}$

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

$\boxed{\rm \: Breadth = total \: distance - Radius}$

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

$\longrightarrow\rm \: Length \: of \: the \: circle = Radius$

Since Length = 6 in ;

$\longrightarrow \rm \: 6 \: in = radius$

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

Total Horizontal Distance= 14
Radius = 6

$\longrightarrow\rm \: Breadth = 14-6$

$\longrightarrow\rm \: Breadth = 8 \: in$

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

Length = 6
Breadth = 8

$\longrightarrow\rm \: Area \: of \: Rectangle = 6 \times 8$

$\longrightarrow \rm \: Area \: of \: Rectangle = 48 \: in {}^{2}$

Then, We need to find the area of Quarter circle :

We know that,

$\boxed{\rm Area_{(Quarter \; Circle) } = \cfrac{\pi{r} {}^{2} }{4}}$

Now Substitute their values:

r = radius = 6
π = 3.14

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 6 {}^{2} }{4}$

Solve it.

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 36}{4}$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}$

$\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \: {in}^{2}$

Now we can Find out the total Area of composite figure:

We know that,

$\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}$

So Substitute their values:

$\rm Area_{(rectangle)}$ = 48
$\rm Area_{(Quarter Circle)}$ = 28.26

$\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26$

Solve it.

$\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}$

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

$\rule{225pt}{2pt}$

I hope this helps!

3 0

1 year ago

Total profit P is defined as total revenue R -= total cost C, and is given by the function Upper P left parenthesis x right par

Goshia [24]

Answer:

Step-by-step explanation:

P(x) = R(x) - C(x)

Where,

P(x) = Total profit

R(x) = Total revenue

C(x) = Total cost

R(x)equals150.97 x minus 0.3 x squared

R(x) = 150.97x - 0.3x^2

Upper C left parenthesis x right parenthesis equals 4529.10 plus 0.5 x squared.

C(x) = 4529.10 + 0.5x^2

P(x) = R(x) - C(x)

= (150.97x - 0.3x^2) - ( 4529.10 + 0.5x^2)

= 150.97x - 0.3x^2 - 4529.10 - 0.5x^2

= 150.97x - 0.8x^2 - 4529.10

P(x) = -0.8x^2 + 150.97x - 4529.10

4 0

3 years ago

Please Help!

vaieri [72.5K]

41.5 times 8.4 is the equation your in high school so you should know the rest

6 0

3 years ago

Read 2 more answers

Find the slope of the line that passes through (-1,6) and (15,6)

svp [43]

Slope = $\frac{Y2 - Y1}{X2 - X1}$
------------------------
6 - 6 = 0
15 - (-1) = 16
0 / 16 = 0
--------------------------------
You have a slope of 0, meaning that this is a straight horizontal line

3 0

2 years ago