Answer:
Explanation:
If the enzyme active site is complementary to the substrate conformation rather than to the transition state, it is unlikely that the reaction will proceed and release a product, because the enzyme-substrate complex will be tightly bound (ΔG will raise).
On the other hand, when the enzyme active site is complementary to the transition state, the substrate will not be tightly bound and will be more prone to be transformed into the product (<u>ΔG will be lowered</u>) and afterward, be released.
The weak interactions (non-covalent bonds) will stabilize the energy of the transition state and reduce its energy, thus lowering the activation energy). If the transition state is stable, it will form more easily and<u> the reaction will be more likely to proceed.</u>
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Answer:
The answer to this question is 33.8
Answer:
Explanation:
In this case, we can start with the <u>formula of Platinum (II) Chloride</u>. The cation is the atom at the left of the name (in this case 
) and the anion is the atom at the right of the name (in this case 
). With this in mind, the <u>formula would be</u> 
.
Now, if we used <u>metallic copper</u> we have to put in the reaction only the <u>copper atom symbol</u> 
. So, we have as reagents:
The question now is: <u>What would be the products?</u> To answer this, we have to remember <u>"single displacement reactions"</u>. With a general reaction:
With this in mind, the reaction would be:
I hope it helps!
Yes because molecules is solid
