Answer:
1.2 × 10³ L
Explanation:
Step 1: Calculate the total number of gaseous moles
n = nH₂ + nCl₂ = 100 mol + 100 mol = 200 mol
Step 2: Convert 30 °C to Kelvin
We will use the following expression.
K = °C + 273.15 = 30 + 273.15 = 303 K
Step 3: Calculate the volume of the container
We will use the ideal gas equation.
P × V = n × R × T
V = n × R × T / P
V = 200 mol × (0.0821 atm.L/mol.K) × 303 K / 4 atm = 1.2 × 10³ L
The number of grams of oxygen present in 1.75 moles of calcium carbonate is 84 grams
Explanation
mass = moles x molar mass
molar mass = 16 g/mol
find the number of moles of oxygen in calcium carbonate as below
formula of calcium carbonate is CaCO3
from the formula above have three(3) atoms of oxygen
therefore the moles of 0xygen = 3 x 1.75 =5.25 moles
mass of oxygen is therefore = 5.25 moles x16g/mol = 84 grams of oxygen
Answer: 1682 kg/m^3
Explanation:
the formula for density is mass/volume
to get the volume of the metal = Final Volume - Initial Volume
= 15.5 - 10.0 = 5.5mL
density of the metal = 9.25g/5.5mL = 1.682g/mL
to convert from g/mL to kg/m^3, multiply by 1000
density of metal = 1682 kg/m^3
The answer is c :) lemme know what you get
Explanation:
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