6. Evaluate f(-1).

3t-8 I’m not sure pls help me

densk [106]

Answer: 3t-8

Step-by-step explanation:

3t-8 is the answer because there are no like terms.

6 0

3 years ago

Please help me with this quadratic equation question! I always give out 5 stars, thanks and brainliest to people that help me wi

ss7ja [257]

Answer:

$p=25,\\q=12$

Step-by-step explanation:

In $(ax+b)(cx+d)=acx^2+bcx+dax+bd$ , notice the third term of the quadratic in standard form is formed entirely by $b\cdot d$ .

Therefore, in $12x^2 - 13x - 7175 = (x-p) (qx + 287)$ :

$-p\cdot287=-7175,\\-p=\frac{-7175}{287},\\p=\fbox{$25$}$ .

Now that we found $p$ , we must find $q$ . The first term of the quadratic in standard form is formed entirely by $ax\cdot cx$ . Therefore:

$1\cdot q=12, \\q=\fbox{$12$}$ .

3 0

2 years ago

Solve using elimination y = 5x+4 y = 2x+7 Show work plz

Gre4nikov [31]

Answer and Step-by-step explanation:

5x + 4

2x + 7

Multiply 5x + 4 by 2, and 2x + 7 by 5.

10x + 8

- 10x + 35

_________

-27 is the answer

#teamtrees #PAW (Plant And Water)

3 0

3 years ago

Find the equation of the line that passes through (4,4) and is parallel to y=2x+4. Leave your answer in the form

Bess [88]

Answer:

y=2x-4

Step-by-step explanation:

If a line is parallel to another line, the only thing that's different in the equation is the y-intercept. Therefore we can solve for the y-intercept using the point (4,4)...

Note that the slope-intercept equation is y=mx+b where b is the y-intercept and m is the slope. x and y are the x and y coordinate pairs.

y=2x+b

4=2(4)+b

4=8+b

b=-4

Therefore the equation of the line that is parallel to y=2x+4 and passes through (4,4) is...

y=2x-4

4 0

2 years ago

Read 2 more answers

Toxaphene is an insecticide that has been identified as a pollutant in the Great Lakes ecosystem. To investigate the effect of t

Likurg_2 [28]

Answer:

This data suggest that there is more variability in low-dose weight gains than in control weight gains.

Step-by-step explanation:

Let $\sigma_{1}^{2}$ be the variance for the population of weight gains for rats given a low dose, and $\sigma_{2}^{2}$ the variance for the population of weight gains for control rats whose diet did not include the insecticide.

We want to test $H_{0}: \sigma_{1}^{2} = \sigma_{2}^{2}$ vs $H_{1}: \sigma_{1}^{2} > \sigma_{2}^{2}$ . We have that the sample standard deviation for $n_{2} = 22$ female control rats was $s_{2} = 28$ g and for $n_{1} = 18$ female low-dose rats was $s_{1} = 51$ g. So, we have observed the value

$F = \frac{s_{1}^{2}}{s_{2}^{2}} = \frac{(51)^{2}}{(28)^{2}} = 3.3176$ which comes from a F distribution with $n_{1} - 1 = 18 - 1 = 17$ degrees of freedom (numerator) and $n_{2} - 1 = 22 - 1 = 21$ degrees of freedom (denominator).

As we want carry out a test of hypothesis at the significance level of 0.05, we should find the 95th quantile of the F distribution with 17 and 21 degrees of freedom, this value is 2.1389. The rejection region is given by {F > 2.1389}, because the observed value is 3.3176 > 2.1389, we reject the null hypothesis. So, this data suggest that there is more variability in low-dose weight gains than in control weight gains.

8 0

3 years ago