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3 years ago

Copper (II) Oxide (CuO) has atoms that form which type of bond?

Chemistry

1 answer:

zysi [14]3 years ago

5 0

Answer:

Copper(II) oxide is a metal oxide that has the formula CuO. It has an ionic structure. It contains a copper(2+). Cupric oxide, or copper (II) oxide, is an inorganic compound with the chemical formula CuO.

Explanation:

I hope that helps you.

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Which model is most likely used to predict a future event

Mandarinka [93]

The model most likely to predict the future event is the model of the weather systems. The model of the weather system provides much crucial information such as the temperature!

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3 years ago

Your town is having a meeting about whether or not to allow residents to build solar panels on their houses. Many people are aga

julsineya [31]

Putting solar panels on houses is a great idea, for it provides a renewable source of energy and heat, which is the sun. It will help prevent pollution and the mass-use of non-renewable resources, such as fossil fuels, which are used and burned for energy.

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3 years ago

Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide. Ca) + H2O --> Ca(OH)2 In a particular

mars1129 [50]

Answer:

Percent yield = 92.5%

Explanation:

The question asks for the percent yield which can be defined as:

$\frac{actual yield}{theoretical yield} .100$

Where the actual yield is <em>how much product was obtained</em>, in this case 6.11 g of Ca(OH)₂, and the theoretical yield is <em>how much product could be obtained with the given reactants theoretically</em>, that is if the reaction would work perfectly. So we need to calculate first the theoretical yield.

1. First lets write the chemical equation reaction correctly and check that it is balanced:

CaO + H₂O → Ca(OH)₂

2. Calculate the amount of product Ca(OH)₂ that can be obtained with the given reactants (theoretical yield), which are 5.00g of CaO and excess of water. So the amount of CaO will determined how much Ca(OH)₂ we can obtained.

For this we'll use the molar ratio between CaO and Ca(OH)₂ which we see it is 1:1. For every mol of CaO we'll obtain a mol of Ca(OH)₂. So lets convert the 5.00 g of CaO to moles:

Molar Mass of CaO: 40.078 + 15.999 = 56.077 g/mol

moles of CaO = 5.00 g / 56.077 g/mol = 0.08916 moles

As we said before from the molar ratio moles of Ca(OH)₂ = moles of CaO

So the moles of Ca(OH)₂ that can be obtained are 56.077 g/mol

We need to convert this value to grams:

Molar Mass of Ca(OH)₂ = 40.078 + (15.999 + 1.008)*2 = 74.092 g/mol

Theoretical yield of Ca(OH)₂ = 0.08916 moles x 74.092 g/mol = 6.606 g

3. Calculate the percent yield:

$\frac{actual yield}{theoretical yield} .100$

Percent yield = (6.11 g / 6.606g) x 100 = 92.5 %

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