Answer:
The resultant velocity of the jet as a vector in component form 426.87 mi/hr 5.36 degrees North.
Explanation:
Vectors are quantities that have their magnitude and direction .
Sketching out the problem given, by using straight lines to represent each of the vectors, we will have a right angled triangle as shown below.
The solution can be obtained by applying Pythagoras theorem to
resolve the vectors.
Velocity of jet plane = 425 mi/hr
velocity of air = 40 mi/hr
Resultant of the vectors =![\sqrt[]{425^{2}+40^{2}}=426.87](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B425%5E%7B2%7D%2B40%5E%7B2%7D%7D%3D426.87)
mi/hr
Vector direction =
hence the velocity is 426.87 mi/hr in a direction 5.36 degrees inclined Northward
This question is a bit ambiguous because all parts of a scientific argument must be supported by valid data. However, among the choices, the closest synonym to "valid data" would be evidence. Evidence is the body of facts or information that support a given idea.
The unstable nuclei undergo radioactive decay. The nucleus decay in form of emitting the radiations or changing into the different chemical element.
Thus, the nucleus decay takes place till the nuclei become stable.
Hence, given statement is false.
A.) We use the famous equation proposed by Albert Einstein written below:
E = Δmc²
where
E is the energy of the photon
Δm is the mass defect, or the difference of the mass before and after the reaction
c is the speed of light equal to 3×10⁸ m/s
Substituting the value:
E = (1.01m - m)*(3×10⁸ m/s) = 0.01mc² = 3×10⁶ Joules
b) The actual energy may be even greater than 3×10⁶ Joules because some of the energy may have been dissipated. Not all of the energy will be absorbed by the photon. Some energy would be dissipated to the surroundings.
The answer is C) the density of the rock
Density of rock is the dependent variable, because it depends on the temperature. The temperature can’t be the dependent variable because ,the density of a rock does not have magical powers that can change temperature of a room. However changing the temperature of the room ,will change the density of the rock. Hope this helps !
