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Aneli [31]
3 years ago
8

An industrial chemist is studying the rate of the haber synthesis: n2 + 3h2 → 2nh3. starting with a closed reactor containing 1.

50 mol/l of n2 and 0.45 mol/l of h2, she finds that the h2 concentration has fallen to 0.16 mol/l after 30. seconds. what is the average rate of reaction of h2 over this time? (enter in mol/liter/sec).
Chemistry
2 answers:
charle [14.2K]3 years ago
4 0
Haber synthesis is preparation of ammonia  
Reacting of nitrogen and hydrogen are at ratio of 1:3 from the equation.
 Change in hydrogen concentration has fallen, so the difference = 0.45 - 0.16  
Change = 0.29 moles/l
 Now average rate of reaction for hydrogen = Change / t = 0.29 / 30 = 0.0096 moles/liter/sec
andre [41]3 years ago
3 0
Haber process is the large scale manufacture of a ammonia by reacting nitrogen and hydrogen at a ratio of 1:3
Change in hydrogen concentration is 0.45 - 0.16 = 0.29 moles/l
Therefore, the average rate of reaction of hydrogen = 0.29 / 30 = 0.0096 
   = 0.0096 moles/liter/sec
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A 33.69 g sample of a substance is initially at 29.4 °c. after absorbing 1623 j of heat, the temperature of the substance is 110
Sliva [168]
Q= mcΔT
1623 = 33.69g x c x (110.8 - 29.4)
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4 0
3 years ago
How many moles of NO2 form when<br> 63.25 g N2O5 decompose?<br> 2N2O5→ 4NO2 + 0₂
GREYUIT [131]

Answer:

1.1713 moles

Explanation:

RFM of N2O5= (14*2)+(16*4)=108

Moles of N2O5= Mass/RFM= 63.25/108= 0.5856 moles

Mole ratio of N2O5:NO2 = 2:4

Therefore moles of NO2= 4/2*0.5856= 1.1713 moles

7 0
1 year ago
Match the solutions to the descriptions of the freezing points.a. One mole of the ionic compound Na3PO4 dissolved in 1000 g H2O
rosijanka [135]

Explanation:

Depression in Freezing point

= Kf × i × m

where m is molality , i is Van't Hoff factor, m = molality

Since molality and Kf remain the same

depression in freezing point is proportional to i

i= 2 for CuSO4 ( CuSO4----------> Cu+2 + SO4-2

i=1 for C2h6O

i= 3 for MgCl2 ( MgCl2--------> Mg+2+ 2Cl-)

So the freezing point depression is highest for MgCl2 and lowest for C2H6O

so freezing point of the solution = freezing point of pure solvent- freezing point depression

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5 0
2 years ago
PLEASE HELP ME does a liquid have definite or indefinite shape.
andrezito [222]
Definite volume and indefinite shape
8 0
2 years ago
When blood is donated, sodium oxalate solution is used to precipitate Ca2+, which triggers clotting. A 122.0−mL sample of blood
icang [17]

Answer:

[Ca2+] = 3.36 * 10^-8 M

Explanation:

Step 1: Data given

A 122.0−mL sample of blood contains 9.70 * 10^−5 g Ca2+/mL.

A technologist treats the sample with 100.0 mL of 0.1550 M Na2C2O4.

Ksp = 2.30 * 10^−9

Step 2: Calculate mass of Ca2+

Mass Ca2+ = 9.70 * 10^−5 g Ca2+/mL * 122 mL

Mass Ca2+ = 0.011834 grams

Step 3: Calculate moles of Ca2+

Moles Ca2+ = mass Ca2+ / molar mass Ca2+

Moles Ca2+ = 0.011834 grams / 40.078 g/mol

Moles Ca2+ = 2.95 *10^-4 moles = 0.000295

Step 4: Calculate moles of C2O4^2-

Moles C2O4^2- = Molarity * volume

Moles C2O4^2- = 0.1550 M * 0.100 L

Moles C2O4^2- = 0.0155 moles

Step 5: Calculate limiting reactant

Ca2+ is the limiting reactant. It will completely be consumed ( 0.000295 moles).

C2O4^2- is in excess. There will 0.000295 moles be consumed. There will remain 0.0155 - 0.000295 = 0.015205 moles of C2O4^2-

Step 6: Calculate total volume

Total volume = 122.0 mL + 100.0 mL = 222.0 mL = 0.222 L

Step 7: Calculate concentration CaC2O4

[CaC2O4] = 0.000295 mol / 0.222 L

[CaC2O4] = 0.00133 M

Step 8: Calculate concentration of C2O4^2-

[C2O4^2-] = 0.015205 mol / 0.222L

[C2O4^2-] = 0.0685 M

Step 9: Calculate [Ca2+]

Ksp = 2.3 * 10^-9 = [Ca2+] [C2O42-]

2.3 * 10^-9 = X * (X+0.0685)

X = [Ca2+] = 3.36 * 10^-8 M

6 0
3 years ago
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