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babymother [125]
2 years ago
13

Based on the information in the tables, what is the Enthalpy of the solution for each substance? Please help me with this proble

m​

Chemistry
1 answer:
3241004551 [841]2 years ago
5 0

Answer: mg(OH)2 = +37

Rbl = 31

RbOH= -83

mgl2= -144

Explanation: just did it on edge2020

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For the following questions, use a periodic table and your atomic calculations to find the unknown information about each isotop
mafiozo [28]

Answer:

Option B is correct.

4

Explanation:

We know that an atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.

All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example, if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.

In given problem we are given with 2 neutrons of helium. We know that the atomic number of He is 2. Thus Mass number of He is,

Number of neutrons + number of proton

2 + 2 = 4

Thus, option B is correct.

7 0
3 years ago
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Andrews [41]

Answer:

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Explanation:

4 0
3 years ago
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10. Which statement about cellular respiration in plants and animals is true?
kogti [31]

Answer:

Ⓑ Both plants and animals release energy from glucose/sugar in cellular respiration.

3 0
2 years ago
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Which of the following statements is true of an aqueous solution of sodium chloride?
Ilya [14]

Answer:

What are the statements please

Explanation:

4 0
3 years ago
How many grams of CO₂ can be produced from the combustion of 2.76 moles of butane according to this equation: 2 C₄H₁₀(g) + 13 O₂
Vilka [71]

Answer:

485.76 g of CO₂ can be made by this combustion

Explanation:

Combustion reaction:

2 C₄H₁₀(g) + 13 O₂ (g) → 8 CO₂ (g) + 10 H₂O (g)

If we only have the amount of butane, we assume the oxygen is the excess reagent.

Ratio is 2:8. Let's make a rule of three:

2 moles of butane can produce 8 moles of dioxide

Therefore, 2.76 moles of butane must produce (2.76 . 8)/ 2 = 11.04 moles of CO₂

We convert the moles to mass → 11.04 mol . 44g / 1 mol = 485.76 g

5 0
3 years ago
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