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mezya [45]
3 years ago
5

What information can a foliated metamorphic rock provide you about the conditions under which it formed?

Chemistry
1 answer:
Mnenie [13.5K]3 years ago
4 0
A foliated rock forms when the minerals are realigned due to the presence of high temperature and pressure. The minerals align in such a way that the axes are directed to where the pressure was applied.
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What is the concentration of a dextrose solution prepared by diluting 16 mL of a 1.0 M dextrose solution to 25 mL using a 25 mL
seraphim [82]

Answer:

0.64 M

Explanation:

Step 1: Given data

  • Initial concentration (C₁): 1.0 M
  • Initial volume (V₁): 16 mL
  • Final concentration (C₂): ?
  • Final volume (V₂): 25 mL

Step 2: Calculate the final concentration of the dextrose solution

We want to prepare a diluted solution from a concentrated one. We can find the final concentration using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 1.0 M × 16 mL / 25 mL

C₂ = 0.64 M

4 0
3 years ago
13. If a chemist has 12.3 moles of N H 03, what is the mass of the sample?​
user100 [1]

Answer:

209.4831 g

Explanation:

number of moles × molar mass = mass of substance in g

12.3 × ( 14.0067 + 1.00484 × 3 ) = 209.4831 g

3 0
3 years ago
Calculate the change in temperature that occurs when 3.50 x 10^-2kg of copper heated by 635 J of energy. Ccu = 0.385 j/gxC
vovikov84 [41]

Answer:

The change in T° is 47.1 °C

Explanation:

Calorimetry formula to solve this:

Q = m . C . ΔT

We replace the data gien:

635 J = 3.50×10⁻² kg . 0.385 J/g°C . ΔT

In units of C, we have g and the mass (m) is in kg. So let's convert it from kg to g → 3.50×10⁻² kg . 1000 g / 1kg = 35 g. Now we can determine the ΔT:

635 J = 35 g . 0.385 J/g°C . ΔT

635 J / 35 g . 0.385 J/g°C = ΔT

47.1°C = ΔT

6 0
3 years ago
Read 2 more answers
As a whole, plants tend to release more oxygen than carbon dioxide into the environment, but the ratios of gases differ at vario
marshall27 [118]

During the day, due to the existence of sunlight, the procedure of photosynthesis elevations over that of respiration. Photosynthesis uses carbon dioxide to produce carbohydrates removing oxygen as a byproduct. During the night, because there is no sunlight, the rate of photosynthesis decreases. This, therefore, drives the rate of respiration to surpass the speed of photosynthesis. In respiration, oxygen is consumed and carbon dioxide is dismissed.

<h3>What is photosynthesis?</h3>
  • Photosynthesis is the process by which manufacturers use sunlight, water, and carbon dioxide to produce oxygen and energy in the form of sugar.
  • The primary position of photosynthesis is to transform solar energy into chemical energy and then reserve that chemical energy for prospective use. For the most part, the planet's living designs are powered by this process.
  • An illustration of photosynthesis is how plants convert sugar and significance from water, air, and sunlight into energy to grow. Description of photosynthesis is the procedure through which plants use water and carbon dioxide to assemble their food, grow and remove excess oxygen into the air.

To learn more about photosynthesis, refer to:

brainly.com/question/19160081

#SPJ4

3 0
1 year ago
What is the percent by mass of water in Na S04.10H20?
dalvyx [7]

Answer:

                    Percent by mass of water is 56%

Explanation:

                    First of all calculate the mass of hydrated compound as,

Mass of Sodium = Na × 2 = 22.99 × 1 = 45.98 g

Mass of Sulfur = S × 1 = 32.06 × 1 = 32.06 g

Mass of Oxygen = O × 14 = 16 × 14 = 224 g

Mass of Hydrogen = H × 20 = 1.01 × 20 = 20.2 g

Mass of Na₂S0₄.10H₂O = 322.24 g

Secondly, calculate mass of water present in hydrated compound. For this one should look for the coefficient present before H₂O in molecular formula of hydrated compound. In this case the coefficient is 10, so the mass of water is...

Mass of water = 10 × 18.02

Mass of water = 180.2 g

Now, we will apply following formula to find percent of water in hydrated compound,

           %H₂O  =  Mass of H₂O / Mass of Hydrated Compound × 100

Putting values,

                                      %H₂O  = 180.2 g / 322.24 g × 100

                                           %H₂O =  55.92 % ≈ 56%

3 0
3 years ago
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