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4 years ago

What is the mass of 4.75 moles of arsenic trichloride

Chemistry

2 answers:

miskamm [114]4 years ago

7 0

1 mole is equal to 1 moles Arsenic Trichloride, or 181.2806 grams.

olga55 [171]4 years ago

5 0

Molecular weight of Arsenic Trichloride or grams The molecular formula for Arsenic Trichloride is AsCl3. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Arsenic Trichloride, or 181.2806 grams.

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Describe the three ways heat can be transferred-radiation, conduction, and convection

hjlf

An example of radiation can be from a fire since the firs is letting off heat without contact. An example of convection can be boiling water since there are molecules moving in the water (a fluid). An example of conduction can be a tea spoon in a cup of hot tea, the heat is getting transferred froma hot object to a cool object.

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4 years ago

What is the method use to separate sand and water

Slav-nsk [51]

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3 years ago

For which gases does the ratio of PV to RT equal a constant? ideal gases gases at very high pressure gases of very low temperatu

KatRina [158]

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6 0

3 years ago

Read 2 more answers

Nitrogen dioxide is used industrially to produce nitric acid, but it contributes to acid rain and photochemical smog. What volum

Strike441 [17]

Answer:

35.41 L

Explanation:

Given, Volume of Copper = 4.84 cm³

Density = 8.95 g/cm³

Considering the expression for density as:

$Density=\frac {Mass}{Volume}$

So,

So, Mass= Density Volume = 8.95 g/cm³ 4.84 cm³ = 43.318 g

Mass of copper = 43.318 g

Molar mass of copper = 63.546 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{43.318\ g}{63.546\ g/mol}$

Moles of copper = 0.6817 moles

Given, Volume of nitric acid solution = 227 mL = 227 cm³

Density = 1.42 g/cm³

Considering the expression for density as:

$Density=\frac {Mass}{Volume}$

So,

So, Mass= Density Volume = 1.42 g/cm³ 227 cm³ = 322.34 g

Also, Nitric acid is 68.0 % by mass. So,

Mass of nitric acid = $\frac {68}{100}\times 322.34\ g$ = 219.1912 g

Molar mass of nitric acid = 63.01 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{219.1912\ g}{63.01\ g/mol}$

Moles of nitric acid = 3.4786 moles

According to the reaction,

$Cu_{(s)}+4HNO_3_{(aq)}\rightarrow Cu(NO_3)_2_{(aq)} + 2NO_2_{(g)} + 2H_2O_{(l)}$

1 mole of copper react with 4 moles of nitric acid

Thus,

0.6817 moles of copper react with 4*0.6817 moles of nitric acid

Moles of nitric acid required = 2.7268 moles

Available moles of nitric acid = 3.4786 moles

Limiting reagent is the one which is present in small amount. Thus, nitric acid is present in large amount, copper is the limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of copper on reaction forms 2 moles of nitrogen dioxide

So,

0.6817 mole of copper on reaction forms 2*0.6817 moles of nitrogen dioxide

Moles of nitrogen dioxide = 1.3634 moles

Given:

Pressure = 724 torr

The conversion of P(torr) to P(atm) is shown below:

$P(torr)=\frac {1}{760}\times P(atm)$

So,

Pressure = 724 / 760 atm = 0.9526 atm

Temperature = 28.2 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (28.2 + 273.15) K = 301.35 K

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9526 atm × V = 1.3634 mol × 0.0821 L.atm/K.mol × 301.35 K

⇒V = 35.41 L

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3 years ago

Alkalis have a pH above 7.0 and turn litmus paper from red to blue. They feel slippery and soapy on the skin.

maria [59]

The answer is true due to the saponification of the fatty substances on the surface of the skin.

4 0

3 years ago

Read 2 more answers