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larisa86 [58]
4 years ago
15

What is the mass of 4.75 moles of arsenic trichloride

Chemistry
2 answers:
miskamm [114]4 years ago
7 0

1 mole is equal to 1 moles Arsenic Trichloride, or 181.2806 grams.

olga55 [171]4 years ago
5 0
Molecular weight of Arsenic Trichloride or grams The molecular formula for Arsenic Trichloride is AsCl3. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Arsenic Trichloride, or 181.2806 grams.
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Using the graph below please draw a reaction potential energy diagram for a reaction with the
azamat

Answer:

12

Explanation:

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3 years ago
Fill in the coefficients that will balance the following reaction: a0Na + a1H2O → a2NaOH + a3H2
Alexandra [31]
Hey there !  :

<span>2 Na + 2 H2O = 2 NaOH + 1 H<span>2

</span></span>Sodium<span> + </span>Dihydrogen Monoxide<span> = </span><span>Natriumhydroxid</span><span> + </span>Hydrogen

Coefficients:

Reagents  :  Na = 2
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4 0
4 years ago
Read 2 more answers
What properties can be used to identify substance and why?
Elena L [17]

Answer:

All substances can be characterized by their unique sets of physical and chemical properties. Properties that can be determined without changing the composition of a substance are referred to as physical properties. Characteristics such as melting point, boiling point, density, solubility, color, odor, etc.

3 0
3 years ago
What does heat mean in chemistry
Tpy6a [65]

Answer:

Heat is the transfer of energy that results from the difference in temperature between a system and its surroundings. At a molecular level, heat is the transfer of energy that makes use of or stimulates disorderly molecular motion in the surroundings.

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8 0
3 years ago
How much heat is required to vaporize 31.5 gg of acetone (C3H6O)(C3H6O) at 25 ∘C∘C? The heat of vaporization for acetone at this
KiRa [710]

Answer:

≅ 16.81 kJ

Explanation:

Given that;

mass of acetone = 31.5 g

molar mass of acetone = 58.08 g/mol

heat of vaporization for acetone = 31.0 kJ/molkJ/mol.

Number of moles = \frac{mass}{molar mass}

Number of moles of acetone = \frac{31.5}{58.08}

Number of moles  of acetone = 0.5424 mole

The heat required to vaporize 31.5 g of acetone can be determined by multiplying the number of moles of acetone with the heat of vaporization of acetone;

Hence;

The heat required to vaporize 31.5 g of acetone = 0.5424 mole × 31.0 kJ/mol

The heat required to vaporize 31.5 g of acetone = 16.8144 kJ

≅ 16.81 kJ

4 0
4 years ago
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