The electrons in bonds (bonding domains) differ from lone
pairs (non-bonding domains) is because the bonding
domains are bonded to the central atom vs the lone pairs are just stuck on as
extra electrons. The difference of bonding domains from non-bonding
domains is that the bonding domains are bonded to the central atom and the
non-bonding domains are just stuck on as extra electrons.
Answer:
2HgS + 3O2 → 2HgO + 2SO2
The coefficients are: 2, 3, 2, 2
Explanation:
HgS + O2 → HgO + SO2
The equation can be balance as follow:
Put 3 in front of O2 as shown below:
HgS + 3O2 → HgO + SO2
Now we can see that there are 6 atoms of O on the left side of the equation and a total of 3 atoms on the right side. It can be balance by putting 2 in front of HgO and SO2 as shown below:
HgS + 3O2 → 2HgO + 2SO2
Now we have 2 atoms of both Hg and S on the right side and 1atom each on the left. It can be balance by putting 2 in front of HgS as shown below:
2HgS + 3O2 → 2HgO + 2SO2
Now the equation is balanced.
The coefficients are: 2, 3, 2, 2
The law of conservation of mass(matter) states that matter(mass) can neither be created nor destroyed during a chemical reaction but changes from one form to another. An unbalanced equation suggests that matter has been created or destroyed. While a balanced equation proofs that matter can never be created but changes to different form. This is the more reason we have count the atoms of an element on both side of the equation to see if they are balanced irrespective of the new form they assume in the product
Answer:
1. Earth
2. Sun
3. Sun
4. Earth
5. Earth
6.Sun
7. Earth
Explanation:
I'm a lil sus of 3 and 6 but I'm pretty sure it's right.
Answer:
Hydrogen is the smallest chemical element. It has one proton and one electron, making it neutral. However, the ions of hydrogen atom are charged species. Thus, the key difference between hydrogen atom and hydrogen ion is that the hydrogen atom is neutral whereas hydrogen ion carries a charge.
25/2 and 96/X
CROSS MULTIPLY.
2x=2,400.
divide by 2.
x=1,200.
you take the GIVEN MASS of an element, and you put it on top, the coefficient is what it’s over. i believe this is right
