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3 years ago

When a positive ion is formed, the resulting ion is

Chemistry

1 answer:

avanturin [10]3 years ago

3 0

A positive ion is also known as a cation, if that’s what you’re looking for.

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Is the photon is in the IR, UV or visible portion of the electromagnetic spectrum.

DiKsa [7]

Answer:

The different types of radiation are defined by the the amount of energy found in the photons. Radio waves have photons with low energies, microwave photons have a little more energy than radio waves, infrared photons have still more, then visible, ultraviolet, X-rays, and, the most energetic of all, gamma-rays.Explanation: hope this helps god bless you

8 0

2 years ago

Given the reaction represented by the balanced equation:

user100 [1]

Answer:

$mass of CHF_3 = 1/3 \times 9.47 \times 70 =220.97g$

Explanation:

$CH_4(g)+3F_2(g)->3HF(g)+CHF_3$

As given in the question that methane( $CH_4$ ) is taken excess amount

mass of $CHF_3$ depend only on mass of fluorine

mass of $F_2$ =180 g

mole of $F_2$ = $\frac{180}{19}$ =9.47

3 mole of $F_2$ gives 1 mole of $CHF_3$

so 1 mole will give $\frac{1}{3}$ mole of $CHF_3$

therefore,

9.47 mole of $F_2$ will give $\frac{1}{3} \times 9.47$ mole of $CHF_3$

$mass of CHF_3 = 1/3 \times 9.47 \times 70 =220.97g$

7 0

3 years ago

WHICH LAW?

Komok [63]

Please scan the whole entire question

8 0

3 years ago

3) A standard mass of 250.0 g was placed on a balance. The balance said it had a mass of 243.9

Roman55 [17]

Answer:

Explanation:

8 0

3 years ago

4.2 g of 1,4-di-t-butyl-2,5-dimethoxybenzene (250.37 g/mol) were synthesized by reacting 10.4 mL of t-butyl alcohol (MW 74.12 g/

nalin [4]

Answer:

Percentage yield of 1,4-di-t-butyl-2,5-dimethoxybenzene is 41.40%.

Explanation:

Here, in the reaction sulfuric acid is playing the role of catalyst by donating its proton in initial stage of the reaction and in the end of the reaction the proton is returned back to sulfuric acid.

Mass = Density × Volume

Mass of t-butyl alcohol = $0.79 g/mL\times 10.4 mL=8.219 g$

Moles of t-butyl alcohol = $\frac{8.219 g}{74.12 g/mol}=0.11084 mol$

Moles of 1,4-dimethoxybenzene = $\frac{5.6 g}{138.17 g/mol}=0.04052 mol$

According to reaction 2 mol of t-butyl alcohol reacts with 1 mol of 1,4-dimethoxybenzene.

Then 0.11084 moles of t-butyl alcohol will react with :

$\frac{1}{2}\times 0.11084 mole=0.05542 mol$ of 1,4-dimethoxybenzene.

This means that moles of 1,4-dimethoxybenzene are limited and moles of t-butyl alcohol are in excess.So, the moles of product will depend upon the moles of 1,4-dimethoxybenzene.

According top reaction 1 mol of 1,4-dimethoxybenzene gives 1 mol of 1,4-di-t-butyl-2,5-dimethoxybenzene.

Then 0.04052 moles of 1,4-di-t-butyl-2,5-dimethoxybenzene will give:

$\frac{1}{1}\times 0.04052 mol= 0.04052 mol$ of 1,4-di-t-butyl-2,5-dimethoxybenzene.