1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
oksian1 [2.3K]
2 years ago
10

NEED HELP PLEASE!!!

Physics
1 answer:
kenny6666 [7]2 years ago
3 0

Answer:

The gravitational potential energy the barbells have at the maximum height, is P.E. = 3680·h J = 1.10 × 10⁴ units

Where;

h = The maximum height to which he lifts the barbells

Explanation:

The given parameters are;

The  amount of work done by the championship lifter in lifting the weight, W = 1.10 × 10⁴ units

The weight of the barbells lifted by the championship lifter, N = 3680 N

The gravitational potential energy, P.E., the barbells had at their maximum height of lift is given as follows;

P.E. = m × g × h

Where;

m = The mass of the barbells;

g = The acceleration due to gravity = 9.8 m/s²

h = The maximum height to which the barbells are lifted by the championship weight lifter

m × g = The weight of the barbells = 3680 N

∴ P.E. = 3680 N × h = 3680·h J

By the conservation of energy principle, work done by the championship weight lifter = The maximum gravitational potential energy gained by the barbell = The gravitational potential energy at the maximum height, P.E.

∴ The gravitational potential energy the barbells have at the maximum height, P.E. = 3680·h J = W = 1.10 × 10⁴ units

You might be interested in
When is an object magnetic?
Sliva [168]
When it has a magnetic field
7 0
3 years ago
Mary and her younger brother Alex decide to ride the 26 ft diameter carousel at the State Fair. Mary sits on one of the horses i
hammer [34]

Answer:

a_M=1.92a_A

Explanation:

\omega_M=\omega_A = Angular speed

r_M = Distance of Mary = 11.5 ft

r_A = Distance of Alex = 6 ft

Ratio of centripetal acceleration is given by

\dfrac{a_M}{a_A}=\dfrac{\omega_M^2r_M}{\omega_A^2r_A}\\\Rightarrow \dfrac{a_M}{a_A}=\dfrac{r_M}{r_A}\\\Rightarrow a_M=a_A\dfrac{r_M}{r_A}\\\Rightarrow a_M=\dfrac{11.5}{6}a_A\\\Rightarrow a_M=1.92a_A

Mary's centripetal acceleration is 1.92 times the centripetal acceleration of Alex

8 0
3 years ago
Why would a flat sheet of paper and a wad of paper with the same mass not fall through the air at the same rate?
Gelneren [198K]
The flat sheet of paper has more surface area than the crumpled ball
7 0
3 years ago
Read 2 more answers
Two boats start together and race across a 48-km-wide lake and back. boat a goes across at 48 km/h and returns at 48 km/h. boat
jolli1 [7]

Answer:

Time required by boat 1 for the round trip is less than that of boat 2.

Hence, boat 1 wins.

Explanation:

Case 1: Boat 1

Speed of boat = \frac{distance of river}{time}

time = \frac{distance of river}{speed of boat}

While going to another end

time = \frac{distance of river}{speed of boat}

time = \frac{48}{48}

time = 1 hour

While going back,

time = \frac{distance of river}{speed of boat}

time = \frac{48}{48}

time = 1 hour

Total time taken by boat 1 is,

Total time by boat 1 = 1 hour + 1 hour = 2 hour

Total time by boat 1 = 2 hour

Total time taken by boat 1 for the round trip is 2 hour.

Case 2: Boat 2

Speed of boat = \frac{distance of river}{time}

time = \frac{distance of river}{speed of boat}

While going to another end

time = \frac{distance of river}{speed of boat}

time = \frac{48}{24}

time = 2 hour

While going back,

time = \frac{distance of river}{speed of boat}

time = \frac{48}{72}

time = 0.66 hour

Total time taken by boat 2 is,

Total time by boat 1 = 2 hour + 0.66 hour

Total time by boat 1 = 2.66 hour

Total time taken by boat 2 for the round trip is 2.66 hour.

Time required by boat 1 for the round trip is less than that of boat 2.

Hence, boat 1 wins.

5 0
3 years ago
A pin fin of uniform, cross-sectional area is fabricated of an aluminum alloy (k = 160 W/m-K). The fin diameter is D = 4 mm, and
frozen [14]

Answer:

Given that

D= 4 mm

K = 160 W/m-K

h=h = 220 W/m²-K

ηf = 0.65

We know that

m=\sqrt{\dfrac{hP}{KA}}

For circular fin

m=\sqrt{\dfrac{4h}{KD}}

m=\sqrt{\dfrac{4\times 220}{160\times 0.004}}

m = 37.08

\eta_f=\dfrac{tanhmL}{mL}

0.65=\dfrac{tanh37.08L}{37.08L}

By solving above equation we get

L= 36.18 mm

The effectiveness for circular fin given as

\varepsilon =\dfrac{2\ tanhmL}{\sqrt{\dfrac{hD}{K}}}

\varepsilon =\dfrac{2\ tanh(37.08\times 0.03618)}{\sqrt{\dfrac{220\times 0.004}{160}}}

ε = 23.52

5 0
3 years ago
Read 2 more answers
Other questions:
  • During which phase of the moon do neap tides occur?
    15·2 answers
  • Plz help me and I will give u a brainliest in return
    11·2 answers
  • A heavy boy and a lightweight girl are balanced on a massless seesaw. The boy moves backward, increasing his distance from the p
    6·1 answer
  • What is the path of an electron moving at 4 000 m/s perpendicular to a magnetic field of 1.5 T? (me = 9.11 x 10^-31kg)
    13·1 answer
  • Which of the following is an example of the media's influence on government? (3 points)
    11·1 answer
  • What will be the mass of a body at the center of the earth as compared to other places on
    11·2 answers
  • In a tropic level, energy flows from the producer to the primary consumer and to a secondary consumer. True False
    11·1 answer
  • If a car moves with a uniform speed of 2m/s in a circle of radius 0.4m, what is its angular speed?
    10·1 answer
  • CAN SOMEONE PLZ HELP
    5·1 answer
  • An rv is traveling 60 km/h along a highway at night. a boy sitting near the driver of the rv turns a flashlight on and shines it
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!