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oksian1 [2.3K]
3 years ago
10

NEED HELP PLEASE!!!

Physics
1 answer:
kenny6666 [7]3 years ago
3 0

Answer:

The gravitational potential energy the barbells have at the maximum height, is P.E. = 3680·h J = 1.10 × 10⁴ units

Where;

h = The maximum height to which he lifts the barbells

Explanation:

The given parameters are;

The  amount of work done by the championship lifter in lifting the weight, W = 1.10 × 10⁴ units

The weight of the barbells lifted by the championship lifter, N = 3680 N

The gravitational potential energy, P.E., the barbells had at their maximum height of lift is given as follows;

P.E. = m × g × h

Where;

m = The mass of the barbells;

g = The acceleration due to gravity = 9.8 m/s²

h = The maximum height to which the barbells are lifted by the championship weight lifter

m × g = The weight of the barbells = 3680 N

∴ P.E. = 3680 N × h = 3680·h J

By the conservation of energy principle, work done by the championship weight lifter = The maximum gravitational potential energy gained by the barbell = The gravitational potential energy at the maximum height, P.E.

∴ The gravitational potential energy the barbells have at the maximum height, P.E. = 3680·h J = W = 1.10 × 10⁴ units

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Explanation:

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A 500 kilogram marlin and a 20 kilogram salmon are swimming at the same velocity. How does the momentum of the two fish compare?
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Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

Below are the choices that can be found from other sources:

A. The marlin has more momentum. 

<span>B. The salmon has more momentum. </span>

<span>C. Both have the same momentum. </span>

<span>D. Both have no momentum.
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Velocity is speed. Momentum is the product of velocity and mass. Because the Marlin has a much greater mass that means that it's momentum would also be greater. 

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4 0
4 years ago
A 4.30 g bullet moving at 943 m/s strikes a 730 g wooden block at rest on a frictionless surface. The bullet emerges, traveling
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Answer:

(a)2.7 m/s

(b) 5.52 m/s

Explanation:

The total of the system would be conserved as no external force is acting on it.

Initial momentum = final momentum

⇒(4.30 g × 943 m/s) + (730 g × 0) = (4.30 g × 484 m/s) + (730 g × v)

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(b) since, the momentum is conserved, the speed of the bullet-block center of mass would be constant.

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Thus, the speed of the bullet-block center of mass is 5.52 m/s.

4 0
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