Answer:
what do you need help with? Like which type of print each image is?
Explanation:
If they are both traveling with the same speed that means that they will reach other in the middle of the line initially between them. In other word, each will have to travel the same amount before they reach other.
Now you can calculate the time it takes for only one locomotive to travel half of the total distance between them, and that time is equal to the time you are looking for.
Use
t = S1/2 / v
where t-time, S-distance traveled , v-velocity
Answer:
0
7500J
7500J
Explanation:
Given parameters:
Mass of car = 600kg
Velocity = 5m/s
Unknown:
Original kinetic energy = ?
Final kinetic energy = ?
Work used = ?
Solution:
The kinetic energy of a body is the energy due to the motion of a body.
It can be solve mathematically using expression below;
K.E = 
m v²
where m is mass
v is velocity
original kinetic energy;
The car started at rest and v = 0, therefore K.E = 0
Final kinetic energy;
K.E = x 600 x 5² = 7500J
Work done:
Work done = Final K.E - Initial K.E = 7500 - 0 = 7500J
Answer:
B
Explanation:
I hope this is what you need
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Answer:
3.88 × 10^-4 m
Explanation:
Given that a person who weighs 614 N is riding a 85-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally by the two tires. If the gauge pressure in each tire is 9.00 x 10^5 Pa. What is the area of contact between each tire and the ground?
The total weight = 614 + 85
The total weight = 699N
Let the total area of contact = A
Pressure = Force / A
Substitute all the parameters into the formula
900000 = 699 /A
A = 699 / 900000
A = 7.77 × 10^-4 m
The area of contact between each tire and the ground will be = A/2
That is, 7.77 / 2 = 3.88 × 10^-4 m
Therefore, the area of contact between each tire and the ground is 3.88 × 10^-4 m approximately.
