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2 years ago

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If Bill threw a ball straight up on the Moon (g=1.6 m/s2) with a starting velocity of 22m/s from a cliff and it fell past him an

d reached a velocity of 56m/s as it impacted the Moon’s surface below the cliff, how long was the flight time?

1 answer:

kap26 [50]2 years ago

5 0

Answer:

Write two important of physical state

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Define what is boyleâs law?

lawyer [7]

Answer:

Volume of given mass of gas is inversely proportional to pressure of gas

Explanation:

Boyle's law: It states that the volume of given mass of gas is inversely proportional to the pressure of gas at constant temperature.

Mathematical representation:

Suppose, a gas of mass m

T=Constant temperature

V=Volume of gas

P=Pressure of gas

Then, $V\propto\frac{1}{P}$

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3 years ago

The force a magnet exerts on another magnet, on iron or a similar metal, or on moving charges is

In-s [12.5K]

The answer is a magnetic force.

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3 years ago

Read 2 more answers

If 5 mm of rain falls in a 100 m2 field, what volume of rain, in m3, fell in the field?

Nina [5.8K]

The volume of rain that fells in the field is simply given by the area of the field, which is

$A=100 mm^2$

multiplied by the height of rain that fell, which is

$h=5.0 mm$

Therefore, the volume is

$V=hA=(5 mm)(100 mm^2)=500 mm^3$

7 0

3 years ago

If time travel to the future existed, doesn't that mean that the future has already occurred and that we are living in the past?

kodGreya [7K]

Answer:

As of right now the techology has not been invented to time travel

if we were to time travel to the future from where that person travled from would be the past and to them the people from where they came from are living in the past

Explanation:

3 0

3 years ago

A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30°C.

MakcuM [25]

Answer:

b. 9.5°C

Explanation:

$m_i$ = Mass of ice = 50 g

$T_i$ = Initial temperature of water and Aluminum = 30°C

$L_f$ = Latent heat of fusion = $3.33\times 10^5\ J/kg^{\circ}C$

$m_w$ = Mass of water = 200 g

$c_w$ = Specific heat of water = 4186 J/kg⋅°C

$m_{Al}$ = Mass of Aluminum = 80 g

$c_{Al}$ = Specific heat of Aluminum = 900 J/kg⋅°C

The equation of the system's heat exchange is given by

$m_i(L_f+c_wT)+m_wc_w(T-T_i)+m_{Al}c_{Al}=0\\\Rightarrow 0.05\times (3.33\times 10^5+4186\times T)+0.2\times 4186(T-30)+0.08\times 900(T-30)=0\\\Rightarrow 1118.5T-10626=0\\\Rightarrow T=\dfrac{10626}{1118.5}\\\Rightarrow T=9.50022\ ^{\circ}C$

The final equilibrium temperature is 9.50022°C

4 0

3 years ago