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marusya05 [52]
2 years ago
10

Which equation has the solution n = 11?

Mathematics
1 answer:
Anton [14]2 years ago
3 0

Answer:

3n+12=45

Step-by-step explanation:

Because if you take 2 and put it in the place of n 32+12 =45 and take 45 and divide it by 12 and you will get 11.

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How do I find the largest angle of the triangle ??
Novosadov [1.4K]
Answer: 89

43 + x = 132 => Exterior Angle Theorem
                                           ^
The measure of an exterior angle of a triangle is greater than either of the measures of the remote interior angles. That means the two remote interior angle add up to the exterior angle.

x = 89

**To find the last angle: 89 + 43 + x = 180 => Triangle Sum Theorem states that the interior angles of a triangle add up to 180. The last angle would be 48.**

3 0
3 years ago
Calculate the slope of the line that passes through the pair of points. (-5,3) and (6,-1)
postnew [5]
M = (y2-y1)/(x2 -x1)
m = (-1 -3)/(6 + 5)
m = -4/11

answer: slope m = -4/11 (d is your answer)
5 0
3 years ago
Help!?!? Find the volume of the composite figure ​
34kurt

Answer:

288

Step-by-step explanation:

answer is in photo above

6 0
3 years ago
Romb ma obwód równy 32 cm. Jakie jest pole tego rombu, jeżeli jego wysokość ma 3 cm?
Goshia [24]

Answer:

24 cm²

Step-by-step explanation:

Z zadanego powyżej pytania uzyskano następujące dane:

Obwód (obwód) = 32 cm

Wysokość (h) = 3 cm

Obszar rombu (A) =?

Następnie określimy długość boku rombu. Można to uzyskać w następujący sposób:

Obwód, czyli obwód (P) = 32 cm

Strona (y) =?

P = 4 s

32 = 4 s

Podziel obie strony przez 4

s = 32/4

s = 8 cm

Stąd długość boku rombu wynosi 8 cm

Na koniec określimy obszar rombu w następujący sposób:

Długość boków = 8 cm

Wysokość (h) = 3 cm

Obszar rombu (A) =?

A = sh

A = 8 × 3

A = 24 cm²

Dlatego obszar rombu jest

24 cm².

8 0
3 years ago
help The screen in a theatre is 22 ft high and is positioned 10 ft above the floor, which is flat. The first row of seats is 7 f
Stella [2.4K]
 <span>(a.) 
Let's say α is the angle that subtends from the top of the screen to horizontal eye-level. 
Let β be the angle that subtends from the bottom of the screen to horizontal eye-level. 

tanα = (22 + 10 - 4) / x = 28/x 
α = arctan(28/x) 

tanβ = (10 - 4) / x = 6/x 
β = arctan(6/x) 

Ɵ = α - β 
Ɵ = arctan(28/x) - arctan(6/x) 

(b.) 
tanƟ = tan(α - β) = (tanα - tanβ) / (1 + tanα tanβ) 
tanƟ = (28/x - 6/x) / [1 + (28/x)(6/x)] 
tanƟ = (22/x) / [1 + (168/x²)] 
tanƟ = 22x / (x² + 168) 
Ɵ = arctan[22x / (x² + 168)]</span>
4 0
3 years ago
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