<span>The water cycle is like a big circle and doesn’t really have a starting point. There are 4 main stages involved in water cycle i.e. evaporation, condensation, precipitation and runoff, so, I'd say you become water, you evaporate, then you turn into a cloud and rain, then runoff.</span>
CaCO₃ + 2HCl = CaCl₂ + CO₂ + H₂O
n(CaCO₃)=m(CaCO₃)/M(CaCO₃)
n(CaCO₃)=13.00/100.09=0.1299 mol
Δm=13.00+52.65-60.32=5.33 g
m(CO₂)=5.33 g
n(CO₂)=5.33/44.01=0,1211 mol
w=0.1211/0.1299=0,9323 (93.23%)
Answer:
ΔG = - 590.20 kJ/mol
Explanation:
The formula for calculating Gibb's Free Energy can be written as:
ΔG = ΔH - TΔS
Given That:
ΔH = -720.5 kJ/mol
T = 221.0°C = (221.0 + 273.15) = 494.15 K
ΔS° = -263.7 J/K
So; ΔS° = -0.2637 kJ/K if being converted from joule to Kilo-joule
Since we are all set, let replace our given data in the above equation:
ΔG = (-720.5 kJ/mol) - (494.15 K) ( - 0.2637 kJ/K)
ΔG = (-720.5 kJ/mol) - (- 130.30755)
ΔG = -720.5 kJ/mol + 130.30755
ΔG = -590.192645 kJ/mol
ΔG = - 590.20 kJ/mol
Thus, The value of ΔG° at 221.0°C for the formation of phosphorous trichloride from its constituent elements, P2(g) + 3Cl2(g) → 2PCl3(g) is <u>-590.20</u> kJ/mol.
Answer:
Aluminium metal reacts vigorously with all the halogens to form aluminium halides. So it reacts with chlorine, bromine, and iodine.
Answer:
Esto significa que la masa en las moles de plomo es mayor que en las de plata.
Explanation:
Las moles de los átomos representan la cantidad de átomos presentes. Para saber la masa de los átomos debemos convertir las moles a gramos usando el peso molecular de cada uno de los átomos (207.2g/mol para el plomo y 107.82g/mol para la plata).
La masa de plomo en 300 moles es:
300 moles * (207.2g / mol) = 62160g de plomo
Y la masa de plata es:
300 moles * (107.82g / mol) = 32346g de plata
<h3>Esto significa que la masa en las moles de plomo es mayor que en las de plata</h3>
