First, find moles of oxygen gas: (3.01 x10^23 molec.)/(6.02 x10^23) =0.5mol O2
Second, multiply moles by the standard molar volume of a gas at STP:(0.5mol)(22.4L) = 11.2L O2
Answer: V = 5.1 L
Explanation: To find the new volume, we will use the formula of Combined Gas Law and derive V2. We also need to convert first the temperature in Kelvin and convert torr to atm ( 1 atm = 760 torrs ).
Solution attached.
Answer:
PV=nRT where P=pressure in atm, V=volume is liters, n=numbber of moles, R=gas constant, 0.08206 L-atm/mole KL, and T=temperature in K (273 + C). So (5.67atm)(99.39L)=n(0.08206 L-atm/mol.K)(328.94K), solve for n, the number of moles, n=20.9 moles.
Explanation:
The p sublevel holds 6 electrons because it has 3 orbitals.