The force that gravitation exerts upon a body, equal to the mass of the body times the local acceleration of gravity is known as weight.
Weight is the force of gravity acting on a body.
The formula is :
W =mg
Here,
W is the weight or force acting on the body. m is the mass of the body, and g is the gravitational acceleration.
Since weight is also a force, so its SI unit is also newton. The value of weight varies from place to place depending on the gravity. Its value can also be equal to zero.
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The solution to your problem is as follows:
<span>5km/h2 x 1 h/60 min x 1 min/60 sec x 1000m/km = 1.39 meters per second change each second.
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Therefore, the speed change each second is <span>1.39 meters per second change each second.
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Given the following choices;
A) less than your true weight, mg.
B) equal to your true weight, mg.
C) more than your true weight, mg.
D) could be more or less than your true weight, mg, depending on the value of the speed.
The answer is; C
This is due to G-force. These are the perception of the weight of an object that is accelerating against gravity. We experience 1 g force on the surface of the earth because the ground exerts an upward exertion against gravity preventing as from falling to the center of the earth.
<span>The number of the group identifies the column of the standard periodic table in which the element appears.</span>
Group 1 contains the alkali metals ( lithium<span> (</span>Li<span>), </span>sodium<span> (</span>Na<span>), </span>potassium<span> (</span>K<span>), </span>rubidium<span> (</span>Rb<span>), </span>caesium<span> (</span>Cs<span>), and </span>francium(Fr).)<span>
Group 2 contains the alkaline earth metals (</span> beryllium<span> (</span>Be),magnesium<span> (</span>Mg<span>), </span>calcium<span> (</span>Ca<span>), </span>strontium<span> (</span>Sr<span>), </span>barium<span> (</span>Ba<span>) and </span>radium<span> (</span>Ra<span>) )
Group 3: </span><span> Scandium (Sc) and yttrium (Y) </span>
Answer:
u = 10.63 m/s
h = 1.10 m
Explanation:
For Take-off speed ..
by using the standard range equation we have
R = 9.1 m
θ = 26º,
Initial velocity = u
solving for u
u = 10.63 m/s
for Max height
using the standard h(max) equation ..
h = 1.10 m