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3 years ago

How high above the ground would a 10 kg object needs to be to have the same GPE as the 30 kg object in the example

Physics

1 answer:

Black_prince [1.1K]3 years ago

4 0

Answer:

The 10 kg mass would have to be at a height 3 times that of the 30 kg mass to have the same gravitational potential energy as the 30 kg mass.

Explanation:

Gravitational potential energy, U = mgh where m = mass of object, g = acceleration due to gravity = 9.8 m/s² and h = height of object above the ground.

Now, let U' = gravitational potential energy of 10 kg mass = m'gh' where m' = 10 kg and h' = height of 10 kg mass above the ground.

So, U' = 10gh'

Also, let U" = gravitational potential energy of 30 kg mass = m"gh" where m" = 30 kg and h" = height of 30 kg mass above the ground.

So, U" = 30gh"

Since both object are supposed to have the same potential energy at a given height of the 10 kg mass,

U' = U"

10gh' = 30gh"

h' = 30gh"/10g

h' = 3h"

So, the 10 kg mass would have to be at a height 3 times that of the 30 kg mass to have the same gravitational potential energy as the 30 kg mass.

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4 years ago

The two blocks in oscillate on a frictionless surface with a period of 1.5 s. The upper block just begins to slip when the ampli

Setler79 [48]

Answer:

0.72

Explanation:

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$A$ = Amplitude of oscillation = 40 cm = 0.40 m

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3 years ago

A 9.00-cm-long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wi

m_a_m_a [10]

Answer:

0.45 N

Explanation:

Let Recall that,

The power formula is:

P = E²/R

Let A = the magnetic field

Let L = length of wire = 9.00cm = 0.09 m

let R = resistance of wire = 0.320 Ω

let v = velocity of the wire = 4 m/s

Let E = across the wire voltage

Let P = the power of the wire = 4.3 W

To Solve for E:

The formula of E = √PR

The Voltage from a magnetic field is given as,

E = vAL

We therefore Use E = E

√PR = vAL

to solve for A,

A= √PR/vL

BA= √4.3(0.32)/(4)(.09) -=0.173

A = 0.173 wA/m²

Let F be the pulling force

Let I be the current in the wire

P = I²R

I = √P/R

F = IAL

F = √P/RAL

F = √4.3/.32(0.173)(.09)

F = 0.45N

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3 years ago

A force of 50 N is used to move a footstool 3 m. How much work is done?

vaieri [72.5K]

The work done is 150 joules

Explanation:

Work occurs when a force (F) acts on an object to move it some

distance (d) from the start point

→ Work done = F × d

The S.I unit of work is Joule

A force of 50 N is used to move a footstool 3 m

→ F = 50 N

→ d = 3 m

→ Work done = F × d

Substitute the values of F and d in the rule

→ Work done = 50 × 3 = 150 joules

The work done is 150 joules

Learn more

You can learn more bout work done in brainly.com/question/9100769

#LearnwithBrainly

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