All categories

3 years ago

How high above the ground would a 10 kg object needs to be to have the same GPE as the 30 kg object in the example

Physics

1 answer:

Black_prince [1.1K]3 years ago

4 0

Answer:

The 10 kg mass would have to be at a height 3 times that of the 30 kg mass to have the same gravitational potential energy as the 30 kg mass.

Explanation:

Gravitational potential energy, U = mgh where m = mass of object, g = acceleration due to gravity = 9.8 m/s² and h = height of object above the ground.

Now, let U' = gravitational potential energy of 10 kg mass = m'gh' where m' = 10 kg and h' = height of 10 kg mass above the ground.

So, U' = 10gh'

Also, let U" = gravitational potential energy of 30 kg mass = m"gh" where m" = 30 kg and h" = height of 30 kg mass above the ground.

So, U" = 30gh"

Since both object are supposed to have the same potential energy at a given height of the 10 kg mass,

U' = U"

10gh' = 30gh"

h' = 30gh"/10g

h' = 3h"

<u>So, the 10 kg mass would have to be at a height 3 times that of the 30 kg mass to have the same gravitational potential energy as the 30 kg mass.</u>

You might be interested in

If you dropped a ball off a building, how far would it fall in 3 seconds?

tangare [24]

If you drop a ball off a building it increases its speed by 10 m/s so in 3 seconds it’s speed would be 30 m/s and it’s distance would be 45m

4 0

4 years ago

A circular loop of wire 75 mm in radius carries a current of 113 A. Find the (a) magnetic field strength and (b) energy density

Roman55 [17]

The magnetic field strength is 9.47 ×10⁻⁴ T

The energy density at the center of the loop is 0.36 J/m³

<h3>Calculating Magnetic field strength & Energy density </h3>

From the question, we are to find the magnetic field strength

The magnetic field strength of a loop can be calculated by using the formula,

$B = \frac{\mu_{0} I}{2R}$

Where B is the magnetic field strength

$\mu_{0}$ is the permeability of free space $(\mu_{0}=4\pi \times 10^{-7} \ N/A^{2})$

$I$ is the current

and R is the radius

From the give information,

$R = 75 \ mm= 75 \times 10^{-3} \ m$

and $I = 113 \ A$

Putting the parameters into the formula, we get

$B = \frac{4\pi \times 10^{-7} \times 113}{2 \times 75 \times 10^{-3} }$

$B = 9.47 \times 10^{-4} \ T$

Hence, the magnetic field strength is 9.47 ×10⁻⁴ T

Now, for the energy density

Energy density can be calculated by using the formula,

$u_{B} = \frac{B^{2} }{2\mu_{0} }$

Where $u_{B}$ is the energy density

Then,

$u_{B}= \frac{(9.47\times 10^{-4} )^{2} }{2 \times 4\pi \times 10^{-7} }$

$u_{B} = 0.36 \ J/m^{3}$

Hence, the energy density at the center of the loop is 0.36 J/m³

Learn more on Magnetic field stregth & Energy density here: brainly.com/question/13035557

7 0

2 years ago

which is true? light waves do not change speed as they travel from air through water. light waves speed up as they travel from t

Alex17521 [72]

light waves slow down as they travel from the air through the water

6 0

4 years ago

2. A 15.0 N force is used to hold a mass on a string at an angle of 32° from the vertical, as in the

castortr0y [4]

Answer: 2.9kg

let mass be=m ; F=15N; Sin(theta)=32°;g =9.8kgm/s^2.

represent the mass. By resolving forces, we have:

F=mgSin(theta)

15N=mgSin(32°)

m=15N/g×Sin(32°)

m=15N/9.8m/s^2÷Sin(32°)

=2.888kg2.888

≈2.9kg

5 0

3 years ago

A free falling object has the velocity time graph shown. What is the objects displacement between 0.0 and 6.0s

zloy xaker [14]

For free fall motion the displacement can be found by graphically as well as by kinematics equation

Here acceleration of object is constant as it fall due to gravity so we can use

$d = v_i * t + \frac{1}{2}at^2$

here if body starts with zero initial speed then we can say

$d = 0 + \frac{1}{2}*9.8*t^2$

here we need to find the displacement from t = 0 to t = 6s

so we can say

$d = \frac{1}{2}*9.8*6^2$

$d = 176.4 m$

so the displacement will be 176.4 m

in order to find the displacement from the graph of velocity and time we need to find the area under the graph for given time interval that will also give us same displacement for given period of time.

6 0

4 years ago

Read 2 more answers