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Zepler [3.9K]
3 years ago
13

How high above the ground would a 10 kg object needs to be to have the same GPE as the 30 kg object in the example

Physics
1 answer:
Black_prince [1.1K]3 years ago
4 0

Answer:

The 10 kg mass would have to be at a height 3 times that of the 30 kg mass to have the same gravitational potential energy as the 30 kg mass.

Explanation:

Gravitational potential energy, U = mgh where m = mass of object, g = acceleration due to gravity = 9.8 m/s² and h = height of object above the ground.

Now, let U' = gravitational potential energy of 10 kg mass = m'gh' where m' = 10 kg and h' = height of 10 kg mass above the ground.

So, U' = 10gh'

Also, let U" = gravitational potential energy of 30 kg mass = m"gh" where m" = 30 kg and h" = height of 30 kg mass above the ground.

So, U" = 30gh"

Since both object are supposed to have the same potential energy at a given height of the 10 kg mass,

U' = U"

10gh' = 30gh"

h' = 30gh"/10g

h' = 3h"

<u>So, the 10 kg mass would have to be at a height 3 times that of the 30 kg mass to have the same gravitational potential energy as the 30 kg mass.</u>

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The cement bag shown in the figure has a mass of 50 kg and the small pulley has a mass of 2 kg. If the cement bag is pulled upwa
GuDViN [60]

For the cement bag we can say as per its force diagram we will have

2F - mg = ma

here we will have

m = 50 kg

a = 2 m/s^2

now we will have

F = \frac{mg + ma}{2}

now plug in all data

F = \frac{50(9.8 + 2)}{2}

F = 295 N

so the pulling force will be 295 N

3 0
3 years ago
A blacksmith heats a 35 g lump of iron from room temperature until it glows (2425 degrees C) to work it. If the specific heat of
Drupady [299]

Answer:

37.9 kJ

Explanation:

We can calculate the thermal energy gained by the iron using the formula:

Q=m C_s \Delta T

where

m = 35 g is the mass of the iron

Cs = 0.450 j/g is the iron's specific heat capacity

\Delta T= 2425 C - 20 C = 2405 C is the change in temperature of the iron (assuming that the room's temperature is 20 C degrees)

Substituting numbers into the formula, we find

Q=(35 g)(0.450 J/g)(2405 C)=3.79\cdot 10^4 J=37.9 kJ

6 0
3 years ago
Using 1000 j of work, a toy elevator is raised from the ground floor to the second floor in 20 s. how much power does the elevat
Anastasy [175]
Power (watts) = work done (joules) ÷ time (seconds)

power (watts) = 1000J ÷ 20s

power (watts) = 50w

3 0
3 years ago
a radio controlled car rolls 10 m south then reverses direction and rolls 8 m north the car traveled a distance of 18 m and has
EastWind [94]

The displacement is 2 m south

Explanation:

Distance and displacement are two different quantities:

  • Distance is the total length of the path covered by an object during its motion, regardless of the direction. It is a scalar quantity
  • Displacement is a vector connecting the initial position to the final position of motion of an object. The magnitude of the displacement is the distance in a straight line between the two points

For the car in this problem, the motion is:

10 m south

8 m north

Taking north as positive direction, we can describe the two parts of the motion as

d_1 = -10 m

d_2 = +8 m

Therefore,  the final position of the car with respect to the original position is

x_f = -10 + 8 = -2 m

which means 2 m south: so, the displacement of the car is 2 m south.

Learn more about  distance and displacement:

brainly.com/question/3969582

#LearnwithBrainly

5 0
3 years ago
Somebody please help
suter [353]

Answer:

a = 0.1067 [m/s²]

Explanation:

In order to solve this problem, we must first draw a free body diagram with the forces acting on it.

a)

In the attached image we can find the free body diagram.

b)

The net force can be found by performing a sum of forces on the X-axis, these forces are seen in the free body diagram.

∑Fx = Fr

where:

Fr = resultant force [N] (units of Newtons)

F_{r}=275+275-310\\F_{r}=240[N]

c)

Acceleration can be found by means of Newton's second law, which tells us that the sum of the forces in a body or the resulting force is equal to the product of mass by acceleration.

∑F = m*a

where:

m = mass = 2250 [kg]

a = acceleration [m/s²]

240=2250*a\\a=0.1067[m/s^{2} ]

5 0
3 years ago
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