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ohaa [14]
3 years ago
5

Orion Balatik Big Dipper Apparent Brightness Absolute Brightness Polaris Star Trail Malihe Gemini Buwaya 1. Local constellation

that signifies the start of rainy season in the Philippines. 2. Local constellation that appears in the month of March. 3. It is seen in the Philippines during the months of April and May. 4. The constellation where we can find Merak and Dubhe. 5. It is the brightes star in the constelation Ursa Minor (Little Dipper). 6. It is a type of photograph that utilizes long-exposure times to capture the apparent motion of stars in the night sky due to the rotation of the Earth. 7. The star's brightness as seen from the Earth. 8. The brightness of the stars if they are at the same standard distance from Earth. 9. This constellation means hunter and is prominent in the night sky all over the world during winter. 10. The local constellation that appears on the month of February and signifies start of planting and setting of traps to protect the crops from animals.​
Physics
1 answer:
Roman55 [17]3 years ago
4 0
I’m nit sure about this but I say it’s 4 the constellation where we can find Merak and Dubhe.
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Un montañero de 65kg de masa ha ascendido a la cima del Everest, la montaña más alta del mundo de 8848m de altura sobre el nivel
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Answer:

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

Explanation:

Por la definición de trabajo sabemos que el montañero debió contrarrestar trabajo causado por la gravedad terrestre. Si asumimos que el cambio de la altura es muy pequeño en comparación con el radio del planeta (6371 kilómetros vs. 0,5 kilómetros), entonces podemos considerar que la aceleración gravitacional es constante y la ecuación de trabajo (\Delta W), medido en joules, que reducida a:

\Delta W = m\cdot g\cdot \Delta z (1)

Donde:

m - Masa del montañero, medido en kilogramos.

g - Aceleración gravitacional, medida en metros por segundo al cuadrado.

\Delta z - Distancia vertical de ascenso del montañero, medida en metros.

Si tenemos que m = 65\,kg, g = 9,807\,\frac{m}{s^{2}} y \Delta z = 500\,m, entonces el trabajo realizado por el montañero para subir es:

\Delta W = (65\,kg)\cdot \left(9,807\,\frac{m}{s^{2}} \right)\cdot (500\,m)

\Delta W = 318727,5\,J

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

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If y = 0.02 sin (30x – 200t) (SI units), the frequency of the wave is
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Answer:

31.831 Hz.

Explanation:

<u>Given:</u>

  • \rm y = 0.02\sin(30x-200 t).

The vertical displacement of a wave is given in generalized form as

\rm y = A\sin(kx -\omega t).

<em>where</em>,

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  • x = horizontal displacement of the wave.
  • \omega = angular frequency of the wave = \rm 2\pi f.
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On comparing the generalized equation with the given equation of the displacement of the wave, we get,

\rm A=0.02.\\k=30.\\\omega =200.\\

therefore,

\rm 2\pi f=200\\\\\Rightarrow f = \dfrac{200}{2\pi}=31.831\ Hz.

It is the required frequency of the wave.

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