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Luba_88 [7]
3 years ago
13

HELP 100 PTS WILL BE GIVEN ASAPPP

Physics
2 answers:
aliina [53]3 years ago
3 0

Answer:

1. Resistance

2. Store chmical energy and transfer it to electrical energy when a circuit is connected

3.Electric current

4. Series and parallel

5. can't see diagram

6. series

7. Parallel

8. can't not see diagram

Explanation:

andrew11 [14]3 years ago
3 0

Answer:

1. Resistance

2. Store chemical energy and transfer it to electrical energy when a circuit is connected

3. Electric current

4. Series and parallel

5. cell (battery)

6. series

7. Parallel

8. Diagram B

9. 12Ω resistor

10. protect equipment by stopping the flow of electric current; protect your house from fire.

11. GFCI outlets prevent electrocution if you are touching a wet appliance. GFCI outlets are found in wet areas.

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Objects that transmit some light and reflect/absorb the rest of the light, like stained glass, are
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You are correct it is translucent because opaque let’s no light through but transparent lets almost all light through
3 0
4 years ago
12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor = how
UkoKoshka [18]

Answer:

12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor are equivalent to 6 drinks.

Explanation:

In the United States, a standard "drink" of beer has 12 ounces, a standard "drink" of wine has 5 ounces and standard drink of liquor has 1.5 ounces. Then, we obtain the quantity of drinks by dividing the total volume of each drink by its respective unit volume and summing each term. That is:

N = \frac{12\,oz}{12\,\frac{oz}{dr} }+\frac{12\,oz}{5\,\frac{oz}{dr} }+\frac{3\,oz}{1.5\,\frac{oz}{dr} }

N = 1\,dr+2.4\,dr+2\,dr

N = 5.4\,dr

N = 6\,dr

12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor are equivalent to 6 drinks.

8 0
3 years ago
A long, straight metal rod has a radius of 5.75 cm and a charge per unit length of 33.3 nC/m. Find the electric field at the fol
PIT_PIT [208]

Answer:

Explanation:

From the question;

We will make assumptions of certain values since they are not given but the process to achieve the end result will be the same thing.

We are to calculate the following task, i.e. to determine the electric field at the distances:

a)  at 4.75 cm

b)  at 20.5 cm

c) at 125.0 cm

Given that:

the charge (q) = 33.3 nC/m

= 33.3 × 10⁻⁹ c/m

radius of rod = 5.75 cm

a) from the given information, we will realize that the distance lies inside the rod. Provided that there is no charge distribution inside the rod.

Then, the electric field will be zero.

b) The electric field formula E = \dfrac{kq }{d}

E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{0.205}

E = 1461.95 N/C

c) The electric field E is calculated as:

E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{1.25}

E = 239.76 N/C

7 0
3 years ago
Which diagram is the best model for a solid?<br> Substance A<br> Substance B<br> О Substance C
mina [271]

Answer:

This link was diagram

Explanation:

https://doubtnut.app.link/FnsNC80Dccb

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3 years ago
A police officer at rest at side of highway notices speeder moving at 62 km/h along road.when speeder passes ,officer accelerate
Korolek [52]

To answer the following questions for this specific problem:

a. 11.48 secs

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<span>c. 9.1 secs. </span>

I am hoping that this answer has satisfied your query about and it will be able to help you.

4 0
3 years ago
Read 2 more answers
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