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Soloha48 [4]
3 years ago
15

A rigid cylinder with a movable piston contains a sample of gas. At 300. K, this sample has a pressure of 240. Kilopascals and a

volume of 70.0 milliliter. What is the volume of this sample when the temperature is changed to 150. K and the pressure is changed to 160. Kilopascals?
Chemistry
2 answers:
iren [92.7K]3 years ago
6 0

Answer:

The volume of this sample when the temperature is changed to 150 K and the pressure is changed to 160 kPa is 52.5 mL.

Explanation:

Boyle's law says that: "The volume occupied by a certain gaseous mass at constant temperature is inversely proportional to pressure" and is expressed mathematically as:

P * V = k

where k is a constant.

Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, which is maintained at a constant pressure, by means of a constant of proportionality that is applied directly. So Charles's law is a law that mathematically says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

\frac{V}{T}=k

Gay-Lussac's law states that the pressure of a fixed volume of a gas is directly proportional to its temperature. In other words, if the volume of a certain quantity of ideal gas remains constant, the quotient between pressure and temperature remains constant:

\frac{P}{T}=k

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

\frac{P*V}{T}=k

Considering an initial state 1 and a final state 2, it is satisfied:

\frac{P1*V1}{T1}=\frac{P2*V2}{T2}

In this case:

  • P1: 240 kPa
  • V1: 70 mL
  • T1: 300 K
  • P2: 160 kPa
  • V2: ?
  • T2: 150 K

Replacing:

\frac{240 kPa*70 mL}{300 K}=\frac{160 kPa*V2}{150 K}

Solving:

V2=\frac{150 K}{160 kPa} *\frac{240 kPa*70 mL}{300 K}

V2= 52.5 mL

<u><em>The volume of this sample when the temperature is changed to 150 K and the pressure is changed to 160 kPa is 52.5 mL.</em></u>

Gelneren [198K]3 years ago
6 0

Answer:

52.5

Explanation:

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Answer:

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Explanation:

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3 0
4 years ago
What mass of powdered drink mix is needed to make 0.5 M solution of 100 ml
Vladimir [108]

Answer:

There is 17,114825 g of powdered drink mix needed

Explanation:

Step 1 : Calculate moles

As given, the concentration of the drink is 0.5 M, this means 0.5 mol / L

Since the volume is 100mL, we have to convert the concentration,

⇒0.5 / 1   =  x /0.1    ⇒ 0.5* 0.1  = x = 0.05 M

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e

Step 2 : calculate mass of the powdered drink

here we use the formula n (mole) = m(mass) / M (Molar mass)

⇒ since powdered drink mix is usually made of sucrose (C12H22O11) and has a molar mass of 342.2965 g/mol.

0.05 mol = mass / 342.2965 g/mol

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nadya68 [22]

If C3H8O is dissolved in water, it would be expected to be a strong electrolyte.

<h3>What is a strong electrolyte?</h3>

A strong electrolyte is a solute or solution (already an electrolyte) that can completely dissociates in solution.

C3H8O is one of those compounds expected to be a strong electrolyte.

Thus, if C3H8O is dissolved in water, it would be expected to be a strong electrolyte.

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III) Si = [Ne] 3s2 3p2

Explanation:

The Moeller diagram or Diagonals Rule is used to remember the order of filling of the atomic orbitals. It is simply a mnemonic rule.

The way to construct this diagram is to write the atomic energy levels (from 1 to 7) and the corresponding sub-levels next to it. Then diagonal lines are drawn from top to bottom.

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