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3 years ago

Write the NET IONIC EQUATION between iron and copper (II) sulfate.

Chemistry

1 answer:

ratelena [41]3 years ago

7 0

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of iron and copper (II) sulfate is given as:

$Fe(s)+CuSO_4(aq.)\rightarrow FeSO_4(aq.)+Cu(s)$

Ionic form of the above equation follows:

$Fe(s)+Cu^{2+}(aq.)+SO_4^{2-}(aq.)\rightarrow Fe^{2+}(aq.)+SO_4^{2-}(aq.)+Cu(s)$

As, sulfate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$Fe(s)+Cu^{2+}(aq.)\rightarrow Fe^{2+}(aq.)+Cu(s)$

Hence, the net ionic equation is written above.

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Complete the equations showing how 2−phenylethanol (c6h5ch2ch2oh) could be prepared from 2−phenylethanoic acid (c6h5ch2co2h) as

avanturin [10]

We are asked to provide an equation for the transformation of 2-phenylethanoic acid to 2-phenylethanol. This type of a reaction is converting a carboxylic acid to an alcohol, which is classified as a reduction reaction since we are decreasing the number of bonds to oxygen in the molecule. In order to reduce a carbonyl to an alcohol, we need a source of hydride, H⁻. Reducing the carboxylic acid once will convert it to the aldehyde. However, we need to reduce the functional group all the way down to an alcohol, which is another reduction step after aldehyde formation. Therefore, the hydride source of choice is lithium aluminum hydride, LiAlH₄.

A reaction scheme is provided to show the reaction of the reduction of carboxylic acid to alcohol. The first step is addition of lithium aluminum hydride which does the reduction, and the second step is a work-up of acid which protonates the alcohol to get the final product.

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2 years ago

12.Calculate the wavelength of an object moving with a velocity of 5 x105 m s-1

uranmaximum [27]

Answer:

Wavelength, $\lambda=3.3\times 10^{-18}\ m$

Explanation:

We have,

Velocity of the object, $v=5\times 10^5\ m/s$

Mass of the object, $m=4\times 10^{-22}\ kg$

It is required to find the wavelength of the object. The relation between wavelength and velocity of the object is given by :

$\lambda=\dfrac{h}{mv}$

h is Planck's constant

$\lambda=\dfrac{6.6\times 10^{-34}}{4\times 10^{-22}\times 5\times 10^5}\\\\\lambda=3.3\times 10^{-18}\ m$

So, the wavelength of the object is $3.3\times 10^{-18}\ m$ .

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3 years ago

A sample of oxygen gas in one container has a volume of 20.0mililiter at 297 K and 101.3 kPa. The entire sample is transferred t

VashaNatasha [74]

Answer: $V_2=\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}$

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

$V_2=\frac{P_1V_1T_2}{T_1P_2}$

where,

$P_1$ = initial pressure of gas = 101.3 kPa

$P_2$ = final pressure of gas = 94.6 kPa

$V_1$ = initial volume of gas = 20.0 ml

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $297K$

$T_2$ = final temperature of gas = $283K$

Now put all the given values in the above equation, we get the final volume of gas.

$V_2=\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}$

$V_2=20.4ml$

Thus the correct numerical setup for calculating the new volume is $\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}$

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3 years ago

Give the formulas for all of the elements that exist as diatomic molecules under normal conditions. See if you can do this witho

GenaCL600 [577]

Answer:

They are:

H2, N2, O2, F2, Cl2, Br2, and I2.

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3 years ago

List the four groups attached to the central carbon of an amino acid.

IrinaVladis [17]

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3 years ago

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