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ELEN [110]
3 years ago
13

Write the NET IONIC EQUATION between iron and copper (II) sulfate.

Chemistry
1 answer:
ratelena [41]3 years ago
7 0

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of iron and copper (II) sulfate is given as:

Fe(s)+CuSO_4(aq.)\rightarrow FeSO_4(aq.)+Cu(s)

Ionic form of the above equation follows:

Fe(s)+Cu^{2+}(aq.)+SO_4^{2-}(aq.)\rightarrow Fe^{2+}(aq.)+SO_4^{2-}(aq.)+Cu(s)

As, sulfate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

Fe(s)+Cu^{2+}(aq.)\rightarrow Fe^{2+}(aq.)+Cu(s)

Hence, the net ionic equation is written above.

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The period of a ripple on a lake is half a second. what is the frequency of the wave
Nataly_w [17]

Answer:

2 Hertz

Explanation:

<em>The frequency would be 2 Hertz.</em>

<u>The frequency of a wave is defined as the rate at which the particles of a medium vibrates when the wave is passed through it while the period of a wave is the time it takes the particles to make a complete cycle of vibration.</u>

The frequency of a wave is inversely related to its period and is defined by the following equation:

f = 1/t, where f is the frequency (in hertz) and t is the period (in seconds).

Hence, if the period of a ripple is 1/2 or 0.5 seconds, the frequency becomes;

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3 years ago
How many atoms of iodine are in 12.75g of CaI2? Hint. How many Iodines are there in one CaI2 particle?
xenn [34]

Answer:

5.225x10^{22}atoms\ I

Explanation:

Hello!

In this case, since 12.75 g of calcium iodide has the following number of moles (molar mass = 293.89 g/mol):

n_{CaI_2}=12.75gCaI_2*\frac{1molCaI_2}{293.89gCaI_2}=0.0434molCaI_2

In such a way, since 1 mole of calcium iodide contains 2 moles of atoms of iodine, and one mole of atoms of iodine contains 6.022x10²³ atoms (Avogadro's number), we compute the resulting atoms as shown below:

atoms\ I=0.0434molCaI_2*\frac{2molI}{1molCaI_2} *\frac{6.022x10^{23}atoms\ I}{1molI} \\\\atoms\ I = 5.225x10^{22}atoms\ I

Best regards!

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3 years ago
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<u><em>For Example:</em></u>

Let us take the example of BF₃

BF₃ contains no proton so it is not a Bronsted Lowery Acid

However, BF₃ has an incomplete octet with 6 electrons. It needs an electron pair to complete its octet. It accepts a pair of electron to become a Lewis Acid

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