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Anarel [89]
3 years ago
5

Is the molecule H2+ stable?

Chemistry
2 answers:
Verdich [7]3 years ago
8 0

Answer: yes it is

Explanation:Bond order

The antibonding orbital is empty. Thus, H2 is a stable molecule

Genrish500 [490]3 years ago
3 0
Answer: Yes

The antibonding orbital is empty. Thus, H2 is a stable molecule.
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A species that is formed when a base gains conjugate base. b. conjugate acid. a proton is a c. strong base d. strong acid.
SSSSS [86.1K]

Answer:

The correct option is: conjugate acid

Explanation:

Bases are the chemical substances that are proton acceptors and electron-pair donors. Therefore, when a base accepts a hydrogen proton from an acid it forms a conjugate acid.

Therefore, conjugate acids are formed when a base accepts a hydrogen proton from an acid. Also, if the base is a weak base then its conjugate acid is strong. Whereas, if the base is a strong base then the conjugate acid is weak.

4 0
3 years ago
Can someone please help and I will mark you as brainlist!!
padilas [110]
The answer for the first one is the second option.

The answer for the second one is the last option.

Hope this helped and have a nice day : )

5 0
3 years ago
At 20 degrees Celsius the density of mercury is 13.6 g/cm cubed. What is the mass of 50.0 ml of mercury at 20 degrees Celsius?
Lynna [10]

Answer:

680g of mercury is the mass of the sample of mercury.

Explanation:

Density is an unit used to relates the mass of an object per unit of volume.

For example, in the problem, the density of mercury is 13.6g/cm³, as cm³ is equal to milliliters, mL, the density is: 13.6g/mL.

If you have 50.0mL of mercury, the mass is:

50.0mL * (13.6g / mL) =

<h3>680g of mercury is the mass of the sample of mercury.</h3>
4 0
3 years ago
1125 J of energy is used to heat 250 g of iron to 55 °C. The specific heat capacity of iron is 0.45 J/(g·°C).
Stolb23 [73]

Answer:

45 °C.

Explanation:

From the question given above, the following data were obtained:

Heat (Q) = 1125 J

Mass (M) = 250 g

Final temperature (T₂) = 55 °C

Specific heat capacity (C) = 0.45 J/gºC

Initial temperature (T₁) =?

The initial temperature of the iron can be obtained as illustrated below:

Q = MC(T₂ – T₁)

1125 = 250 × 0.45 (55 – T₁)

1125 = 112.5 (55 – T₁)

Divide both side by 112.5

1125/112.5 = 55 – T₁

10 = 55 – T₁

Collect like terms

10 – 55 = –T₁

–45 = –T₁

Multiply through by –1

45 = T₁

T₁ = 45 °C

Therefore, the initial temperature of the iron is 45 °C

8 0
3 years ago
352 mL of chlorine exerts a pressure of 680 mmHg. What will the volume
Drupady [299]

Answer:

The answer would be 0.198 liters.

Explanation:

Message me for any questions.

7 0
3 years ago
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