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babymother [125]
4 years ago
13

*explain your answer for brainliest

Chemistry
1 answer:
Over [174]4 years ago
3 0

Answer:

3 mol Cl₂/2 mol AlCl₃ (three over two)

Step-by-step explanation:

Start with the balanced equation"

2Al + 3Cl₂⟶ 2AlCl₃

The steps in the calculation are

mass of AlCl₃ ⟶ moles of AlCl₃⟶ moles of Cl₂ ⟶ mass of Cl₂

The critical step is the <em>conversion of moles</em>.

You multiply the moles of AlCl₃ by a <em>conversion factor</em> to get moles of Al:

Moles of AlCl₃ × conversion factor = moles of Al.

The conversion factor is <em>the molar ratio</em>, and it uses the coefficients of the formulas in the balanced equation.

It is either (2 mol AlCl₃/3 mol Cl₂) or (3 mol Cl₂/2 mol AlCl₃).

You choose the one that has the desired units of the answer in the numerator.

We choose the second option, because it has the correct units.

For example,

\text{0.2 mol AlCl}_{3} \times \frac{3\textbf{ mol Cl}_{2} }{ 2\text{ mol AlCl}_{3} } = 0.3\textbf{ mol Cl}_{2})

Notice how the units "mol AlCl₃" cancel and the correct units appear in the answer.

If we had used the other conversion factor, we would have gotten the wrong units.

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Point N is on line segment MO. Given NO = 2x – 3, MO = 3x + 5, and
Zigmanuir [339]

Answer:

MO = 20

Explanation:

Given that: MO = 3x + 5

                  MN = 2x + 3

                  NO = 2x - 3

But,

MO = MN + NO

So that;

3x + 5 = (2x + 3) + (2x - 3)

3x + 5 = 2x + 3 + 2x - 3

3x + 5 = 4x

3x - 4x = -5

-x = -5

Multiply through by minus,

x = 5

Thus,

MO = 3x + 5

      = 3(5) + 5

      = 15 + 5

MO = 20

The length of MO is 20.

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3 years ago
A sample of a metal has a mass of 2272 grams.Its dimensions are 5 cm by 5 cm by 8 cm.
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What produced the sulfuric acid that helped form the Lechugilla caves
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3 years ago
•What was the physical property used by mendeleev<br> in creating his periodio table?<br>Answer!​
Vsevolod [243]

Answer:

Explanation: Mendeleev arranged the elements on the basis of their atomic mass. Melting and boiling point were used as the physical characteristics in deciding the position of elements. He arranged the elements and wrote the formula of their oxides and hydrides which seemed to possess same chemical formula.

Explanation:

7 0
4 years ago
How many molecules would there be in 10.5 L of carbon dioxide at 40.0 C and 252 kPa
kakasveta [241]

Answer:

6.14×10²³ molecules

Explanation:

Data obtained from the question include:

Volume (V) = 10.5L

Temperature (T) = 40°C

Pressure (P) = 252 kPa

Next, we shall determine the number of mole of CO2 present.

This can be obtained by using the ideal gas equation:

PV = nRT

Volume (V) = 10.5L

Temperature (T) = 40°C = 40°C + 273 = 313K

Pressure (P) = 252 kPa

Gas constant (R) = 8.31 KPa.L/Kmol

Number of mole (n) =.?

PV = nRT

252 x 10.5 = n x 8.31 x 313

Divide both side by 8.31 x 313

n = (252 x 10.5) /(8.31 x 313)

n = 1.02 mole

Therefore, 1.02 mol of CO2 is present.

Now, we can obtain the number of molecules of CO2 present as follow:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02×10²³ molecules.

This means that 1 mole of CO2 also contains 6.02×10²³ molecules.

Now, if 1 mole of CO2 contains 6.02×10²³ molecules,

Then 1.02 mole will contain = 1.02 x 6.02×10²³ = 6.14×10²³ molecules.

Therefore, 6.14×10²³ molecules of CO2 is present.

8 0
4 years ago
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