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77julia77 [94]
3 years ago
11

The reaction below will occur in a gaseous system at STP:

Chemistry
1 answer:
WARRIOR [948]3 years ago
4 0

Answer:

V = 12.5 L

Explanation:

Given data:

Volume of NO = 15.0 L

Temperature and pressure = standard

Volume of nitrogen gas produced = ?

Solution:

Chemical equation:

6NO + 4NH₃    →     5N₂ + 6 H₂O

Number of moles of NO:

PV = nRT

n = PV/RT

n = 1 atm × 15.0 L / 0.0821 atm.L /mol.K × 273.15 K

n = 15.0 atm.L / 22.43 atm.L /mol

n = 0.67 mol

now we will compare the moles of No and nitrogen gas.

              NO           :         N₂

               6             :          5

              0.67         :         5/6×0.67 = 0.56

Volume of nitrogen gas:

 PV = nRT

1 atm × V = 0.56 mol ×  0.0821 atm.L /mol.K × 273.15 K

V = 12.5 atm.L / 1 atm

V = 12.5 L

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2.53×10²³ atoms

Explanation:

To solve this, convert grams to moles and moles to atoms.

To convert grams to moles, use the molar mass of C₁₂H₂₂O₁₁ (342.296 g/mol).  Divide the mass by the molar mass to get moles.  Moles = 0.4207

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2 years ago
How many grams of NO will be produced from 60.0g of NO2 reacted with excess water in the following chemical reaction?
Lynna [10]

Answer:

Mass = 19.78 g

Explanation:

Given data:

Mass of NO produced = ?

Mass of NO₂ reacted = 60.0 g

Solution:

Chemical equation:

3NO₂(g) + H₂O(l)   →  2HNO₃(g) + NO(g)

Number of moles of NO₂:

Number of moles = mass/molar mass

Number of moles = 60.0 g/ 46 g/mol

Number of moles = 1.3 mol

Now we will compare the moles of NO₂ with NO.

                      NO₂         :           NO

                        3            :            1

                      1.3            :            1/3×1.3 = 0.43 mol

Mass of NO:

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6 0
3 years ago
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