According to Charles' Law the volume of an ideal gas is directly proportional to its absolute temperature in Kelvin keeping the pressure constant.
V∝ T, P is constant
where V, T and P are volume, temperature and pressure
= 
where V₁, T₁, V₂ and T₂ are initial volume, initial temperature, final volume and final temperature.
Answer:
The answer to your question is below
Explanation:
Physical properties are the properties in which there is no change in the nature of the substance but there is a change in the physical state.
Chemical properties are the properties in which the substance changes its nature. A new substance is formed.
A. Ice melts in the sun. Physical p.
B. Copper is a shiny metal. Physical p.
C. Paper can burn. Chemical p.
D. A silver knife can tarnish. Physical p.
E. A magnet removes iron particles from a mixture. Physical p.
The identity of the metal is copper.
<h3>What is specific heat?</h3>
The amount of energy needed to raise the temperature of one gram of a substance by one degree Celsius.
Using the formula of specific heat
H = mcdT
Where, H = Heat absorbed
m = mass of the metal
c = specific heat capacity of the metal
dT = temperature change
Putting the values in the equation
20 J = 0.0052 Kg × c × ( 40.0°C - 30.0°C)
c = 20 J/0.0052 Kg × ( 40.0°C - 30.0°C)
c = 385 JKg-1°C-1
Thus, the metal is copper.
Learn more about specific heat
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Linking monomers together to form a polymer .This chemical reaction also forms water molecules.
<h3>What is Polymerization?</h3>
This is a type of reaction which involves the linking of two or more monomers to form a polymer.
Dehydration reaction forms water molecules as part of the product thereby making it the most appropriate choice.
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The volume of O₂ produced: 84.6 L
<h3>Further explanation</h3>
Given
7.93 mol of dinitrogen pentoxide
T = 48 + 273 = 321 K
P = 125 kPa = 1,23365 atm
Required
Volume of O₂
Solution
Decomposition reaction of dinitrogen pentoxide
2N₂O₅(g)→4NO₂(g)+O₂ (g)
From the equation, mol ratio N₂O₅ : O₂ = 2 : 1, so mol O₂ :
= 0.5 x mol N₂O₅
= 0.5 x 7.93
= 3.965 moles
The volume of O₂ :
