A 53 kg gymnast applies a vertical ground reaction force of 1,080 N at 0.13 m behind the center of mass during a forward somersa
1 answer:
Answer:
Torque is 140.4 N-m.
Explanation:
Mass of the gymnast, m = 53 kg
Vertical force acting on the gymnast, F = 1080 N
Distance, r = 0.13 m behind the center of mass during a forward somersault. We need to find the torque generated about the center of mass. The force is acting behind the center of mass. F = -1080 N
Torque is given by :
So, the torque generated about the center of mass is 140.4 N-m.
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Answer:
E = 4.83 N/ C
Explanation:
If we have a uniform charge sphere we can use the following formulas to calculate the Electric field due to the charge of the sphere:
: Formula (1) To calculate the electric field in the region outside the sphere r ≥ a
Where:
K: coulomb constant (N*m²/C²)
a: sphere radius (m)
Q: Total sphere charge (C)
r : Distance from the center of the sphere to the region where the electric field is calculated (m)
Equivalences
1nC=10⁻⁹C
1cm= 10⁻²m
Data
k= 9*10⁹ N*m²/C²
Q=4nC=4 *10⁻⁹C
D = 26 cm = 26*10⁻²m = 0.26m
a = D/2 = 0.13m
r= R+a = 2.6 m+ 0.13m = 2.73m
Problem development
Magnitude of the electric field at r = 2.73m from the center of the sphere
r>a , We apply the Formula (1) :
E= 4.83 N/ C