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Arte-miy333 [17]
3 years ago
8

Number of moles in 37g of magnesium​

Chemistry
1 answer:
Ne4ueva [31]3 years ago
3 0
Rounded its 1.522 mol
You might be interested in
If an ice cube weighing 25.0 g with an initial
riadik2000 [5.3K]

Answer:

11

∘

C

Explanation:

As far as solving this problem goes, it is very important that you do not forget to account for the phase change underwent by the solid water at

0

∘

C

to liquid at

0

∘

C

.

The heat needed to melt the solid at its melting point will come from the warmer water sample. This means that you have

q

1

+

q

2

=

−

q

3

(

1

)

, where

q

1

- the heat absorbed by the solid at

0

∘

C

q

2

- the heat absorbed by the liquid at

0

∘

C

q

3

- the heat lost by the warmer water sample

The two equations that you will use are

q

=

m

⋅

c

⋅

Δ

T

, where

q

- heat absorbed/lost

m

- the mass of the sample

c

- the specific heat of water, equal to

4.18

J

g

∘

C

Δ

T

- the change in temperature, defined as final temperature minus initial temperature

and

q

=

n

⋅

Δ

H

fus

, where

q

- heat absorbed

n

- the number of moles of water

Δ

H

fus

- the molar heat of fusion of water, equal to

6.01 kJ/mol

Use water's molar mass to find how many moles of water you have in the

100.0-g

sample

100.0

g

⋅

1 mole H

2

O

18.015

g

=

5.551 moles H

2

O

So, how much heat is needed to allow the sample to go from solid at

0

∘

C

to liquid at

0

∘

C

?

q

1

=

5.551

moles

⋅

6.01

kJ

mole

=

33.36 kJ

This means that equation

(

1

)

becomes

33.36 kJ

+

q

2

=

−

q

3

The minus sign for

q

3

is used because heat lost carries a negative sign.

So, if

T

f

is the final temperature of the water, you can say that

33.36 kJ

+

m

sample

⋅

c

⋅

Δ

T

sample

=

−

m

water

⋅

c

⋅

Δ

T

water

More specifically, you have

33.36 kJ

+

100.0

g

⋅

4.18

J

g

∘

C

⋅

(

T

f

−

0

)

∘

C

=

−

650

g

⋅

4.18

J

g

∘

C

⋅

(

T

f

−

25

)

∘

C

33.36 kJ

+

418 J

⋅

(

T

f

−

0

)

=

−

2717 J

⋅

(

T

f

−

25

)

Convert the joules to kilojoules to get

33.36

kJ

+

0.418

kJ

⋅

T

f

=

−

2.717

kJ

⋅

(

T

f

−

25

)

This is equivalent to

0.418

⋅

T

f

+

2.717

⋅

T

f

=

67.925

−

33.36

T

f

=

34.565

0.418

+

2.717

=

11.026

∘

C

Rounded to two sig figs, the number of sig figs you have for the mass of warmer water, the answer will be

T

f

=

11

∘

C

Explanation:

3 0
2 years ago
How many grams are in 4 moles of Calcium?
mixer [17]

Answer:

160.32 grams of Ca or 160 if rounded

Explanation:

Multiply moles of Ca by the conversion factor (molar mass of calcium) 40.08 g Ca/ 1 mol Ca, which then allows the cancelation of moles, leaving grams of Ca.

4 mol*40.08g/mol = 160.32 grams of Ca

please give thanks by clicking heart button :)

3 0
2 years ago
Read 2 more answers
Describe the three types of system: a.open: b.closed: c. Isolated:
Mnenie [13.5K]

An open system is when there is a transfer of energy and matter with its surroundings.

A closed system is where there is a transfer of energy, may it be heat or work, but not matter with its surroundings.

An isolated system is where there is no transfer of energy or matter with its surroundings.

4 0
2 years ago
Take a paperclip into water and then slowly pull it upward to the point where it is nearly free from the surface. You'll find th
Mandarinka [93]

Answer:

Adhesive forces and cohesive forces

Explanation:

Cohesive forces is how much the water molecules stick to each other and adhesive forces are to which extinct they stick to other surfaces.

When we pull the paperclip upward the water molecules adhere to it due to adhesive forces. While the water on the clip is remain connected to water in the glass because of cohesive forces.

So if the adhesive forces dominates the water will be pulled out and if the cohesive forces dominate it will remain with other water in the cup.

5 0
2 years ago
Consider the reaction 3X + 2Y → 5C + 4D With excess Y, how many moles of X are needed to produce 21.00 moles of D?​
Elan Coil [88]

Answer:

\huge\boxed{\sf 15.75\ moles }

Explanation:

<u>Given reaction is:</u>

3X + 2Y → 5C + 4D

<u>In this reaction, we have:</u>

For 3 moles of X, 4 moles of D

So,

4D = 3X

Divide both sides by 4

D = 3X/4

Multiply both sides by 21

21D = 3X/4 × 21

21D = 3*21X/4

21D = 63X/4

21D = 15.75X

So, to produce 21 moles of D, we need 15.75 moles of X.

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
7 0
2 years ago
Read 2 more answers
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