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olga nikolaevna [1]
3 years ago
6

The nucleus of an atom can have either a positive or negative charge. please select the best answer from the choices provided t

f
Physics
2 answers:
Airida [17]3 years ago
5 0
F - False.

The nucleus of an atom is positively charge.
Ivahew [28]3 years ago
3 0

Answer:

FALSE

Explanation:

Nucleus of an atom consist of neutrons and protons and it is the smallest part of atom.

So the total charge on the nucleus is due to charge of protons as we know that neutrons are neutral in nature and they do not have any charge on it.

So we will have

Q_{proton} = + 1.6 \times 10^{-19} C

Q_{neutron} = 0 C

Q_{electron} = - 1.6 \times 10^{-19} C

so here we can say that total charge on a nucleus must be positive charge which is only due to protons present inside the nucleus.

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3 years ago
Two charges, qA and qB, are separated by a distance, d, and exert a force, F, on each other. Analyze Coulomb's law and answer th
maria [59]

Answer: a. F doubled

b. F reduced by one-quarter i.e

1/4*(F)

c. 1/9*(F)

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e. F reduces 3/4*(F)

Explanation: Coulombs law states the force F of attraction/repulsion experience by two charges qA and qB is directly proportional to thier product and inversely proportional to the square of distance d between them. That is

F = k*(qA*qB)/d²

a. If qA is doubled therefore the force is doubled since they are directly proportional.

b. If qA and qB are half, that means thier new product would be qA/2)*qB/2 =qA*qB/4

Which means the product of charge is divided by 4 so the force would be divided by 4 too since they are directly proportional.

c. If d is tripped that is multiplied by 3. From the formula new d would be (3*d)²=9d² but force is inversely proportional to d² so instead of multiplying by 9 the force will be divided by 9

d. If d is cut into half that is divided by 2. The new d would be (d/2)²=d²/4. So d² is divided by 4 so the force would be multiplied by 4

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3/4*F

6 0
3 years ago
Suppose that two Scientists use different measurement systems in their work. What problems might arise if they shared their data
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3 0
3 years ago
What average force is needed to accelerate a 9.20-gram pellet from rest to 125 m/s over a distance of 0.800 m along the barrel o
aleksklad [387]
Given:
u = 0, initial velocity
v = 125 m/s, final velocity
s = 0.0800 m, distance traveled
9.20 g, the mass of the pellet

If the acceleration is a, then
0² + 2*(a m/s²)*(0.800 m) = (125 m/s)²
1.6a = 15625
a = 9765.625 m/s²

Calculate the force.
F = (9.20 x 10⁻³ kg)*(9765.625 m/s²) = 98.84 N

Answer: 98.8 N (nearest tenth)
8 0
3 years ago
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