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dmitriy555 [2]
3 years ago
11

Hat do peaked roofs, convertible tops, and airplane wings have in common when air moves faster across their top surfaces? What d

o peaked roofs, convertible tops, and airplane wings have in common when air moves faster across their top surfaces?
a.The pressure underneath them is reduced.
b.The pressure underneath them is increased.
c.The pressure above them is reduced.
d.The pressure above them is increased.
Physics
2 answers:
Nutka1998 [239]3 years ago
6 0

Answer:

a.

Explanation:

The air moves faster across the top of the surface and exerts less pressure on the air below and thus due to difference in air pressure the top roof is lifted.

hence the correct option is pressure underneath them is reduced.

Mumz [18]3 years ago
4 0

Answer:

option (c)

Explanation:

As the wind blows from upper side, then the pressure at the above side is reduced and hence the pressure at the underneath of the surface is increased so that the roofs blown away.

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The coulombic force between two ions is reduced to ______ of its original strength when the distance between them is quadrupled.
gayaneshka [121]

Answer:

<h3>1/16</h3>

Explanation:

According to the coulombs law, the force existing vetween the ions is expressed as;

F = kQq/r² .... 1

Q and q are the ions

r is the distance between the ions

If the distance between the ion is quadrupled, then;

F2 =  kQq/(4r)²

F2 =  kQq/16r² ... 2

Divide equation 2 by 1;

F2/F = kQq/16r² ÷ kQq/r²

F2/F = kQq/16r² × r²/kQq

F2/F = 1/16

F2 = 1/16 F

Therefore the coulombic force between two ions is reduced to<u> 1/16 </u>of its original strength when the distance between them is quadrupled.

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3 years ago
Given a 45 45 90 prism with index of 1.5, immersed in air. The hypotenuse acts as the reflecting face by TIR. A ray of light ent
Genrish500 [490]

Answer:

83.6°

Explanation:

For the ray to be totally internally reflected, at the boundary, the angle of refraction is 90. Using the law of refraction where

n₁sinθ₁ = n₂sinθ₂ where n₁ = refractive index of prism = 1.5, θ₁ = critical angle in prism, n₂ = refractive index of air = 1 and θ₂ = refractive angle = 90°.

So, substituting these values into the equation,

n₁sinθ₁ = n₂sinθ₂

1.5 × sinθ₁ = 1 × sin90

1.5 × sinθ₁  = 1

sinθ₁ = 1/1.5

sinθ₁ = 0.6667

θ₁  = sin*(0.6667)

θ₁  = 41.8°

So, for total internal reflection, an incidence angle of 41.8° is required. So, a full convergence angle of 2 × 41.8° = 83.6° is required for the whole bundle of rays.

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