Answer:
Distance, d = 3242.19 meters
Explanation:
It is given that,
Speed of the dog, v = 19.85 mi/hr
Since, 1 mph = 0.44704 m/s
v = 19.85 mi/hr = 8.873 m/s
Time taken by the dog, t = 6.09 min = 365.4 sec
Let the distance covered by the dog during this time period is d. It can be calculated by the speed of the dog multiplied by the time taken as :
d = 3242.19 meters
So, the the dog travel during this time period is 3242.19 meters. Hence, this is the required solution.
A 'velocity' is built out of a speed and a direction.
The only item on that list that has a speed and a direction is the <em>first one</em>. The speed is 30 m/s and the direction is south.
The largest possible displacement you can get by combining the two of them is if they're both in the SAME direction. You walk 3 meters, stop for a breath, then walk another 4 meters in the same direction as the first one. The resultant is 7 meters.
The smallest possible resultant is 1 meter, if the two displacements are in OPPOSITE directions. This time, you walk 4 meters, stop for a breath, then you TURN AROUND and walk 3 meters back in the direction you came from. You end up 1 meter from where you started.
We have that the time in seconds, minutes, and hours is
From the Question we are told that
Velocity 
Distance 
Generally the equation for the Time is mathematically given as
Therefore
And
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Answer:
Friction can be increased the longer two objects are rubbed together, since the longer they are rubbed is the more heat produced.
Explanation:
