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notka56 [123]
2 years ago
5

If 0.05 mol of I2 were actually produced in a reaction starting with 15 grams of CO what is the percent yield of I2

Chemistry
1 answer:
Andrew [12]2 years ago
4 0

Answer:

6.2

Explanation:

<h2>I AM SMOooOooOooORT</h2><h2 /><h2>no but really trust the process</h2><h2 />
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Hey I'm a newbie any help please with this
solniwko [45]
6 A
7 A
8 B
9 B
10 A
11 C
4 0
3 years ago
An ideal gas contained in a piston-cylinder assembly is compressed isothermally in an internally reversible process.
Tju [1.3M]

Answer:

a) \Delta S

b) entropy of the sistem equal to a), entropy of the universe grater than a).

Explanation:

a) The change of entropy for a reversible process:

\delta S=\frac{\delta Q}{T}

\Delta S=\frac{Q}{T}

The energy balance:

\delta U=[tex]\delta Q- \delta W

If the process is isothermical the U doesn't change:

0=[tex]\delta Q- \delta W

\delta Q= \delta W

Q= W

The work:

W=\int_{V1}^{V2}P*dV

If it is an ideal gas:

P=\frac{n*R*T}{V}

W=\int_{V1}^{V2}\frac{n*R*T}{V}*dV

Solving:

W=n*R*T*ln(V2/V1)

Replacing:

\Delta S=\frac{n*R*T*ln(V2/V1)}{T}

\Delta S=n*R*ln(V2/V1)}

Given that it's a compression: V2<V1 and ln(V2/V1)<0. So:

\Delta S

b) The entropy change of the sistem will be equal to the calculated in a), but the change of entropy of the universe will be 0 in a) (reversible process) and in b) has to be positive given that it is an irreversible process.

7 0
3 years ago
Removing the tip of the stem in a young plant will most directly interfere with the production of
denis23 [38]

Answer:

c.

Explanation:

4 0
2 years ago
While in science class a student measured a cube. She
alexira [117]

Answer:

7cm

Explanation:

6 0
3 years ago
How many amino acids do three nucleotides code for.
s2008m [1.1K]

Answer:

one amino acid

Explanation: its right

4 0
2 years ago
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