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3 years ago

If 0.05 mol of I2 were actually produced in a reaction starting with 15 grams of CO what is the percent yield of I2

Chemistry

1 answer:

Andrew [12]3 years ago

4 0

Answer:

6.2

Explanation:

<h2>I AM SMOooOooOooORT</h2><h2 /><h2>no but really trust the process</h2><h2 />

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What is the chemical name for the balanced equation? 2Al+3Pb(NO3)2=2Al(NO3)3+3Pb

Zigmanuir [339]

The chemical name for reactant side:

Al - Aluminium, Pb(NO3)2 - Lead(II) nitrate.

The chemical name for product side:

Al(NO3)3 - Aluminium nitrate, Pb - lead.

<u>Explanation</u>:

This is an oxidation-reduction (redox) reaction:

3 $Pb^{II}$ + 6 e- → 3 $Pb^{o}$ (reduction)

2 $Al^{o}$ - 6 e- → 2 $Al^{III}$ (oxidation)

Pb(NO3)2 is an oxidizing agent, Al is a reducing agent.

Reactants:

Al uminium

Names: Aluminum, Aluminium powder, Al

Appearance: Silvery-white-to-grey powder, Silvery-white,

malleable, ductile, odorless metal.

Pb(NO3)2 – Lead(II) nitrate

Other names: Lead nitrate, Plumbous nitrate, Lead dinitrate

Appearance: White colorless crystals, White or colorless crystals

Products:

Al(NO3)3 – Aluminium nitrate

Other names: Nitric Aluminum salt, Aluminum nitrate,

Aluminium(III) nitrate

Appearance: White crystals, solid | hygroscopic

Pb - lead

Names: Lead, Lead metal, Plumbum

Appearance: Bluish-white or silvery-grey solid in various forms.

Turns tarnished on exposure to air. A heavy, ductile,

soft, gray solid.

8 0

3 years ago

Draw a formula for Thr-Gly-Ala (T-G-A) in its predominant ionic form at pH 7.3. You may assume for the purposes of this question

Rudiy27

Answer:

gggggggggg

Explanation:

gggggggg

8 0

3 years ago

What is the answer for N2O

charle [14.2K]

Answer:

Nitrous Oxide = N20

Explanation:

8 0

3 years ago

Based on the three formulas shown, use one of them to solve for the purple yellow and red box and explain how you did it.

zysi [14]

P = 11.133 atm (purple)

T = -236.733 °C(yellow)

n = 0.174 mol(red)

<h3>Further explanation </h3>

Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated),:

Boyle's law at constant T, P = 1 / V
Charles's law, at constant P, V = T
Avogadro's law, at constant P and T, V = n

So that the three laws can be combined into a single gas equation, the ideal gas equation

In general, the gas equation can be written

$\large {\boxed {\bold {PV = nRT}}}$

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.08206 L.atm / mol K

T = temperature, Kelvin

To choose the formula used, we refer to the data provided

Because the data provided are temperature, pressure, volume and moles, than we use the formula PV = nRT

Purple box

T= 10 +273.15 = 373.15 K

V=5.5 L

n=2 mol

$\tt P=\dfrac{nRT}{V}\\\\P=\dfrac{2\times 0.08205\times 373.15}{5.5}\\\\P=11.133~atm$

Yellow box

V=8.3 L

P=1.8 atm

n=5 mol

$\tt T=\dfrac{PV}{nR}\\\\T=\dfrac{1.8\times 8.3}{5\times 0.08205}\\\\T=36.42~K=-236.733^oC$

Red box

T = 12 + 273.15 = 285.15 K

V=3.4 L

P=1.2 atm

$\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{1.2\times 3.4}{0.08205\times 285.15}\\\\n=0.174~mol$

3 0

3 years ago

A buffer solution is composed of 4.00 4.00 mol of acid and 3.25 3.25 mol of the conjugate base. If the p K a pKa of the acid is

Reika [66]

<u>Answer:</u> The pH of the buffer is 4.61

<u>Explanation:</u>

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{conjuagate base}]}{[\text{acid}]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of weak acid = 4.70

$[\text{conjuagate base}]}$ = moles of conjugate base = 3.25 moles

$[\text{acid}]$ = Moles of acid = 4.00 moles

pH = ?

Putting values in above equation, we get:

$pH=4.70+\log(\frac{3.25}{4.00})\\\\pH=4.61$

Hence, the pH of the buffer is 4.61

8 0

3 years ago