Answer:
The answer is "6.52 kg and 13.1 kg"
Explanation:
For point a:
Equation:
Calculating the amount of

For point b:

Equation:
Calculating the amount of

Answer: The movement of heat from a warmer object to a cooler one is called heat transfer
Explanation:
Answer:
An Educated Guess
Explanation:
After the scientist is done with the experiment he should do an educated guess, they use the data from the experiments to make charts and graphs to communicate the results of the experiment. After the scientists makes the hypothesis, they perform this procedure.