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saul85 [17]
3 years ago
13

Convert the following temperatures to degrees Celsius or Fahrenheit: (a) 95°F, the temperature on a hot summer day; (b) 12°F,

the temperature on a cold winter day; (c) a 102°F fever; (d) a furnace operating at 1852°F; (e)273.15°C (theoretically the lowest attainable temperature).
Chemistry
1 answer:
Elis [28]3 years ago
4 0

Answer:

a) 35°C, the temperature on a hot summer day

b) -11.11°C, the temperature on a cold winter day

c)  a 38.88°C fever

d) a furnace operating at 1011.11°C

e) 523.67°F ( theoretically the lowest attainable temperature )

Explanation:

  • °C = ( °F - 32 ) / 1.8
  • °F = ( 1.8 * °C ) +32

a) 95°F ⇒ °C = ( 95 - 32 ) / 1.8 = 35°C

b) 12°F ⇒ °C = ( 12 - 32 ) / 1.8 = -11.11°C

c) 102°F ⇒ °C = ( 102 -32 ) / 1.8 = 38.88°C

d) 1852°F ⇒ °C = ( 1852 -32 ) / 1.8 = 1011.11°C

e) 273.15°C ⇒ °F = ( 1.8 * 273.15 ) + 32 = 523.67°F

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Explanation:

Once blood glucose levels increase, pancreatic insulin migrates into a fat cell via the blood stream. Insulin then binds in the plasma membrane of the cell to an Insulin Receptor (IR). Through autophosphorylation, phosphate groups are then added to the IR,  causing GLUT4 molecules to come to the cell's surface.

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The energy required to remove an electron from a neutral atom is known as its:
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Explanation:

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Something that causes a response in an organism is called a(n) _____.
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What is the pH of a 0.640 M solution of C₅H₅NHBr (Kb of C₅H₅N is 1.7 × 10⁻⁹)?
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The pH of a 0.64 M solution of pyridine (C₅H₅N) is 9.52.  

<h3>What is pH ?</h3>

A figure expressing the acidity or alkalinity of a solution on a logarithmic scale on which 7 is neutral, lower values are more acid and higher values more alkaline.

The equation for the protonation of the base pyridine is the following:

C₅H₅N + H₂O ⇄ C₅H₅NH⁺ + OH⁻   (1)

Kb = 1.7 × 10⁻⁹ (Given)

To calculate the pH of the solution we need to use the following equation:

pH + pOH = 14

<em>pH = 14 - pOH</em>

     =14 - [-log[OH⁻]]

    = 14 + log[OH⁻]

Now, we need to find the concentration of the OH⁻ ions. Since pyridine is a weak base, at the equilibrium we have (eq 1):

C₅H₅N  +  H₂O  ⇄  C₅H₅NH⁺  +  OH⁻

0.64 - x                          x              x

After entering the values of [C₅H₅N] = 0.64-x, [C₅H₅NH⁺] = x, and [OH⁻] = x, into equation (2) we can find the concentration of OH⁻:

1.7 × 10⁻⁹  =[C₅H₅NH⁺]  [OH⁻]  /  [C₅H₅N]

                = x . x / 0.64-x

1.7 × 10⁻⁹ (0.64-x) - x² = 0

Solving the above quadratic equation for x, we have :

  • x₁ = -3.32 x 10⁻⁵
  • x₂ = 3.32 x 10⁻⁵

Now, We can calculate the pH, after taking the positive value, x₂, (concentrations cannot be negative) and entering into above equation :

<em />

<em>pH = </em>14 + log[OH⁻]

     = 14 + log (3.32 x 10⁻⁵)

 

     = 9.52

Therefore, the pH of the solution of pyridine is 9.52.

Find more about pH here:

brainly.com/question/8834103?referrer=searchResults

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3 0
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2. The pressure of the oxygen gas inside a
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Answer: 4.41 atm

Explanation:

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Original temperature of oxygen gas (T1) = 25°C

[Convert 25°C to Kelvin by adding 273

25°C + 273 = 298K

New pressure of oxygen gas (P2) = ?

New temperature of oxygen gas (T2) = -10°C

[Convert -10°C to Kelvin by adding 273

-10°C + 273 = 263K

Since pressure and temperature are given while volume is held constant, apply the formula for Charle's law

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5.00 atm /298K = P2/263K

To get the value of P2, cross multiply

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1315 atm•K = 298K•V2

V2 = 1315 atm•K / 298K

V2 = 4.41 atm

Thus, the new pressure inside the canister is 4.41 atmosphere

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